3 years ago

The percent of decrease from 12 to 9.

Mathematics

2 answers:

MissTica3 years ago

7 0

I’m pretty sure it’s 75%

DochEvi [55]3 years ago

3 0

Answer:

75%

Step-by-step explanation:

You might be interested in

What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 1080 mL of a 50 per cent solutio

Jlenok [28]

Answer: 480 mL, 600 mL

Step-by-step explanation:

Given

The concentration of the first acid is 75%

The concentration of the second acid is 30%

The final mixture has a concentration of 50%

The final volume is 1080 mL

Suppose x and y be the volume of the first and second acid

$\therefore x+y=1080\quad \ldots(i)\\0.75x+0.3y=0.5\times 1080\quad \ldots(ii)$

Solving the above equations we get

$x=480,y=600$

So, the quantity of the first acid is 480 mL and 600 mL for the second mixture.

6 0

2 years ago

How do you simplify:<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%28125%20%5E%7B2%7D%20%7D%20%29%20%20%20%5E%7B%20-%20

Nady [450]

Answer:

$\huge\boxed{\sqrt{(125^2)^{-\frac{1}{3}}}=\dfrac{1}{5}}$

Step-by-step explanation:

$\sqrt{(125^2)^{-\frac{1}{3}}}\qquad\text{use}\ (a^n)^m=(a^m)^n\\\\=\sqrt{\left(125^{-\frac{1}{3}\right)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=125^{-\frac{1}{3}}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{125^\frac{1}{3}}\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\dfrac{1}{\sqrt[3]{125}}=\dfrac{1}{5}\qquad\text{because}\ 5^3=125$