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2 years ago

The percent of decrease from 12 to 9.

Mathematics

2 answers:

MissTica2 years ago

7 0

I’m pretty sure it’s 75%

DochEvi [55]2 years ago

3 0

Answer:

75%

Step-by-step explanation:

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PLEASE HELP

Virty [35]

<u>Answer-</u>

$\boxed{\boxed{\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{3}{4}}}$

<u>Solution-</u>

We know that arc length is the product of radius and central angle in radian.

i.e $\text{Arc length}=\text{Radius}\times \text{Central angle}$

Here,

$\theta_{BC}=1.18\ rad,\ \theta_{DE}=2.36\ rad\\\\AD=\dfrac{2}{3}AB\Rightarrow AB=\dfrac{3}{2}AD$

So,

$\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{AB\times 1.18}{AD\times 2.36}$

$=\dfrac{\frac{3}{2}AD\times 1.18}{AD\times 2.36}$

$=\dfrac{3\times 1}{2\times 2}$

$=\dfrac{3}{4}$

4 0

2 years ago

Find the area of the region between two concentric circular paths. If the radii of the circular paths are 210 m. and 490 m. resp

taurus [48]

Given :

The radii of the circular paths are 210 m. and 490 m.

To Find :

The area of the region between two concentric circular paths.

Solution :

Area of the outer circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}}$

⠀

Area of the inner circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}}$

⠀

Therefore,

Area of the region inside the circular paths :

$\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}$

6 0

1 year ago

Help please someone like....

Bas_tet [7]

Answer:

400cm²

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A city planner is mapping out some new features for a triangle park. She sketches the park on a grid paper. The coordinates of t

Alecsey [184]

Answer:

Perhaps, she is interested in finding the area enclosed by this triangular park.

Step-by-step explanation:

The area of the triangle enclosed by the three points

A(1,1), B(1,4) and C(-3,4) in this question will be given by

|Ax ( By − Cy)+ Bx(Cy−Ay)+ Cx(Ay− By) |/2

=|1(4-4)+1(4-1)+-3(1-4)|/2=10/5= 5 sq. units.

5 0

2 years ago

A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).

juin [17]

Answer:

A. $PR = 80.6 yd$

B. Perimeter = 190.6 yd

Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

$PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}$

$PR = \sqrt{(70)^2 + (-40)^2}$

$PR = \sqrt{4,900 + 1,600}$

$PR = \sqrt{6,500}$

$PR = 80.6 yd$ (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

PQ = |50 - 10| = 40 yd

QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

Perimeter = 190.6 yd

7 0

2 years ago