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Likurg_2 [28]
3 years ago
13

What is the longest flagpole ( in whole feet) that could be shipped in a box that measures 2ft by 2 ft by 12 ft

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0
I believe the answer is 12 feet because 12 feet is the longest dimension
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Question : 3/4+ 0.6 = ? 1.15 1.35 1.45 or 1.05
Artyom0805 [142]

we have

\frac{3}{4} +0.6

we know that

\frac{3}{4}=0.75

and

0.75=0.40+0.35

substitute in the expression

0.40+0.35 +0.6

(0.40+0.60)+0.35

(1.00)+0.35=1.35

therefore

<u>the answer is</u>

1.35

3 0
3 years ago
Read 2 more answers
)) Omar used 28 centimeters of tape to wrap 4 presents. How much tape will Omar need in
pav-90 [236]

Answer:

He would need 42 cm *or 14cm

Step-by-step explanation:

28/4 is 7

that means that he used 7 cm of tape per present

6 x 7 is 42

that means that he would need 42 cm of tape

4 to 28

6 to 42

*If he already has 4 presents done and he needs to 2 more present then he would need 14 cm, 2 x 7 is 14

8 0
3 years ago
Dexter has 83 tiles left over from tiling his bathroom floor and he would like to use them to tile the front entrance of his hou
creativ13 [48]

Answer: [0, 396]

Step-by-step explanation:

The domain is the acceptable values of x in the function.  In this case, x = t, the number of tiles.  If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles).  So, the domain for this function is from 0 to 44.

0 to 44 written in interval notation is [0,44].

The range is the acceptable values of y in the function.  In this case, y = A, the area given.  A(t) = 9t, so you can use the acceptable values of t to get the range.  Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.

A(t) = 9t

A = 9(44)

A = 396

With the maximum number of tiles, 44, the area you get is 396 cm².  Therefore, the acceptable values of A are from 0 to 396.

0 to 396 written in interval notation is [0, 396].

4 0
3 years ago
The points R(−4, −1) and S(2, −5) are two vertices of right triangle RST. The hypotenuse of the triangle is RS.
Nostrana [21]
      If RS is the hypotenuse of the triangle RST and point T is in Quadrant 3, then point T must be the intersection of the lines: x = - 4 and y = - 5.
       Therefore, the coordinates of point T are ( x, y ) = ( - 4, - 5 ) 
       Answer:
       T ( - 4, - 5 )
6 0
3 years ago
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Translate the following into verbal phrases. 3x-4
nadezda [96]
Answer:
Three x negative four
7 0
3 years ago
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