Answer:
The answer is: A) The petrochemical industry benefits if accidents do not occur, since accidents involve risk of employee injury as well as loss of equipment and product.
Explanation:
The basis for this statement would be a benefit cost analysis. Organizations make decisions by analyzing the benefits of an action versus the costs of taking that action. If the benefits are higher than the costs, then they will profit from those actions.
In this case, petrochemical industries will probably lose more money if an accident happens than the money they can save form cutting costs on safety procedures. Financially it makes more sense to prevent accidents.
Answer: Williamson industries would have obtained $7.78 billion in sales
Explanation: According to the question, the company is having a total of $2 billion in fixed assets. The fixed assets are currently operating at 90% (0.9) of its total capacity. At his level, the company is able to achieve a sales figure of $7 billion. The implication is as follows;
Fixed assets (at 100%) = 2 billion
Fixed assets (at 90%) = 2 * 0.9
Fixed assets (at 90%) = 1.8
If the company utilizes $1.8 billion to achieve a $7 billion sales figure, then operating at full capacity (100%) would yield the following;
7/x = 90/100
(Where x equals sales level at 100% capacity)
7/x = 0.9
Cross multiply
x = 7/0.9
x = 7.7777...
x ≈ 7.78
Therefore, if Williamson Industries had been operating at full capacity, it would have obtained a sales level of $7.78 billion
Answer:
this is a cost minimization problem, but it is missing some numbers, so I looked for similar questions (see attached PDF):
minimization equation = 20x₁ + 22x₂ + 18x₃ (costs per ton)
where:
x₁ = mine I
x₂ = mine II
x₃ = mine III
the constraints are:
4x₁ + 6x₂ + x₃ ≥ 54 (high grade ore)
4x₁ + 4x₂ + 6x₃ ≥ 65 (low grade ore)
x₁, x₂, x₃ ≤ 7 (only 7 days per week)
using solver, the optimal solution is
2x₁, 7x₂, and 5x₃
a. The number of days Mine I should operate = <u>2 days
</u>
b. The number of days Mine Il should operate = <u>7 days
</u>
c. The number of days Mine III should operate = <u>5 days
</u>
d. The total cost of the operation for next week = <u>$284,000</u>
Answer:
I hav this same question :(
Explanation:
