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Andrej [43]
3 years ago
11

32 customers in 4 checkout lanes

Mathematics
2 answers:
viva [34]3 years ago
5 0
I don’t know what the question is but it would be 8 divides out evenly
KIM [24]3 years ago
5 0
32 divided by 4 equals 8
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What is the medium lower quartile upper quartile and interquartil of the numbers
docker41 [41]
First you find the median, by taking 893+954 and dividing the sum of those two numbers by 2. The median is 923.5. Then you take and find the median of the numbers before the median which is 513. That is your lower quartile. Then you find the median of the numbers below the median, which is 1038. That is your upper quartile. The interquartile range is your upper quartile minus your lower quartile.  

Therefore, your answer would be: 
Median- 923.5
Lower Quartile- 513
Upper Quartile- 1038
Interquartile Range- 525

3 0
3 years ago
Write an algebraic equation to represent the situation
8090 [49]

Answer:

C. 2d+3=12

Step-by-step explanation:

6 0
2 years ago
What are the solutions to the equation x - 7/x = 6
bearhunter [10]

The answer is C that is X=7 and X=-1

multiple x through the given equation to get rid of a fraction. It will be

{x}^{2}  - 7 = 6x

After that bring 6X to the LHS of the equation

so that it will look like the general equation that is

{x}^{2}  - 6x - 7 = 0

Use the quadratic formula (or any other approach to find the values of x

You will arrive at

x = 7. - 1

3 0
3 years ago
How would you simplify the expression represented by the diagram below?
luda_lava [24]
6 + 3c is the correct answer
3 0
2 years ago
Read 2 more answers
Please show your work and explain it.
Maru [420]

Answer:

f(x)=\dfrac{x+2}{2(x-2)}

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}

Next we factor what we can so we can further simplify the rest of the equation:

=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\

We can now cancel out (x+2)

=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}

Next we factor out even more:

=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

=\dfrac{(x+2)(1)}{(x-2)(2)}

And we can now simplify it to:

=\dfrac{x+2}{2(x-2)}

6 0
3 years ago
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