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3 years ago

Use the equation Y = {/27x-54 +5.

Mathematics

1 answer:

astra-53 [7]3 years ago

7 0

Answer:

y= 34x- 2 +5 (C)

Step-by-step explanation:

The equation: y = 27x-54 +5

We are to determine an equivalent equation of the form y=avx -h+k from the options given.

From the above, av = two digit coefficient of x. Hence av is constant.

h and k are also constant.

Let's check out the option to find the equation that is in the form y=avx-h+k

a) y=-273x + 2+5

In this equation, the coefficient of x is a 3-digit number. The option is wrong.

b) y=-3x+2 +5

In this equation, the coefficient of x is a 1-digit number. The option is wrong.

c) y=34x -2 +5

In this equation, the coefficient of x is a 2-digit number.

av = 34, h= 2 and k = 5

This equation is in the form of y=avx -h+k

The option is correct.

d) y=273/x-2 +5

This equation is not in the form of y=avx -h+k

The option is wrong.

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lorasvet [3.4K]

Answer: Less

Step-by-step explanation:

If you break down each fraction into a decimal form you will get,

4/12 = 0.33

4/6 = 0.66

Making 4/12 less than 4/6.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Is it possible for the function f(x) - 5 x 2^x to have an output of 200?

Advocard [28]

Answer:

The solution is possible

Step-by-step explanation:

Given

$f(x) = 5 * 2^x$

Required

Is an output of 200, possible?

To know if it is possible or not, we start by substituting 200 for f(x)

$200 = 5 * 2^x$

Divide both sides by 5

$\frac{200}{5} = \frac{5}{5} * 2^x$

$\frac{200}{5} = 2^x$

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$2^x =40$

Take logarithm of both sides

$log2^x =log40$

Apply law of logarithm

$xlog2 =log40$

Divide both sides by log2

$x = \frac{log40}{log2}$

$x = \frac{1.6021}{0.3010}$

$x = 5.32$

for f(x) = 200, x is approximately 5.32

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3 years ago

What is the value of x in the equation 25x = 16?

k0ka [10]

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

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Step 1: Divide both sides by 25.

25x2

x2=

Step 2: Take square root.

x=±√

x=0.8,−0.8

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2 years ago