I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is

Answer:
18.7
Step-by-step explanation:
The Law of Cosines is
, where c is the unknown side length of a triangle, a and b are the remaining two side lengths, and C is the angle opposite to side c. To answer this question just plug in the known values:

Simplify:



m≈18.665...
When rounded to the nearest tenth, m=18.7
Answer:
44
Step-by-step explanation:
Formula

Your scale is 2cm to 2units therefore the parameters are as follows
h=4
b1=9
b2=13




If the number of terms is one then it is called a mono-nomial
if number of terms is two then it is called binomial.
if the number of terms is three or more than three then it is called poly-nomial.