-3x=2x+19
-19 -19
-3x-19=2x
+3x +3x
-19=5x
/5 /5
x=19/5
Polygons, Number of sides, Measure is angles, and angle sums
Answer:
Step-by-step explanation:
Assuming 'x' the distance helicopter needs to fly to be directly over the tower.
It is given that a helicopter flying 3590 feet above ground spots the top of a 150-foot tall cell phone tower at an angle of depression of 83°.
From attachment that helicopter, tower and angle of depression forms a right triangle.
As height of tower is 150 feet, so the vertical distance between helicopter and tower will be: 3590-150=3440 feet.
Also, the side with length 3590-150 feet is opposite and side x is adjacent side to 83° angle.
As the tangent relates the opposite side of a right triangle to its adjacent side, so we will use tangent to find the length of x.
=>
Thus, the helicopter must fly approximately 422.4 feet to be directly over the tower.
Answer:
see explanation
Step-by-step explanation:
If there is a solution between x = 1.1 and x = 1.2 then there will be a change in sign when the equation is evaluated at the points, indicating the graph has crossed the x- axis, where the solution lies.
Given
x³ + 4x = 6 ( subtract 6 from both sides )
x³ + 4x - 6 = 0 ← in standard form
Evaluating for x = 1.1
(1.1)³ + 4(1.1) - 6
= 1.331 + 4.4 - 6 = - 0.269 ← < 0
Evaluating for x = 1.2
(1.2)³ + 4(1.2) - 6
= 1.728 + 4.8 - 6 = 0.528 ← > 0
Since there is a change in sign the graph has crossed the x-axis from below / indicating a solution between x = 1.1 and x = 1.2
Answer: The question is incomplete, here is the complete question ;
Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose that for banner-tailed kangaroo rats, X has an exponential distribution with parameter ? = 0.01327. (a) What is the probability that the distance is at most 100 m? At most 200 m? Between 100 and 200 m? (Round your answers to four decimal places.
Step-by-step explanation:
- X = denote the distance (m)
- P (X > x) = exp( - 0.01342x)
- Therefore, P (X < = 100) = 1 - P (X > 100) = e-0.01342 X 100 = 0.2613 ; the probability that the distance is at most 100 m
- Similarly, P (X < =200) = e-0.01342 X 200 = 0.0683 ; At most 200 m
- P(100 < X <200) = 0.2613 - 0.0683 = 0.193 ; Between 100 and 200 m