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3 years ago

My cousin needs help with this one. ⬆

Mathematics

1 answer:

mina [271]3 years ago

4 0

If you are talking about "Write a number sentence that shows the sum of the 4 color of stars.

1/8 + 1/8 + 1/8 + 1/8 = 4/8, or 1/2

is your answer

for a number sentence, write out the whole thing with the equal sign and the answer

hope this helps

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The legal permitted speed limit for all vehicles near a school zone is

Alenkasestr [34]

C. 25 miles per hour

8 0

3 years ago

Read 2 more answers

In the sequence 400, 200, 150, 75, 25...... what number comes next

Scorpion4ik [409]

Answer:

The next term in the sequence = -175

Step-by-step explanation:

Here, the given sequence is : 400, 200, 150, 75, 25...

Now here, in the given sequence,

First Term - Second Term = 400 - 200 = 200

Second Term - Third Term = 200 - 150 = 50

Third term - Fourth Term = 150 - 75 = 75

Fourth term - Fifth term = 75 - 25 = 50

So, following this pattern,

Fifth Term - Sixth term = 200

Or, 25 - Sixth Term = 200

or, Sixth term = 25 - 200 = - 175

Hence, the next term in the sequence = -175

4 0

3 years ago

Distributive property for 144 divided by 8 (5th grade)

Oksi-84 [34.3K]

18144 divided by 8 Distributive property

7 0

3 years ago

An article reports "sales have grown by 30% this year, to $200 million." What were sales before the growth? An article reports "

zimovet [89]

The amount of sales before growth according to the article is $153.85 million

<h3>How to find sales before growth?</h3>

let

Sales before growth = x
Percentage growth = 30%
New sales = $200 million

200 = x + (30% × x)

200 = x + (0.3 × x)

200 = x + 0.3x

200 = 1.3x

x = 200/1.3

x = 153.846153846153

Approximately,

x = $153.85 million

Learn more about percentage:

brainly.com/question/843074

#SPJ1

8 0

2 years ago

Kara did a survey to determine to study the types of pets that students in her school had. She surveyed 300 students and found t

julsineya [31]

Answer:

Step-by-step explanation:

Total Number of Students =300

Percentage who had cats, n(C) = 40%

Percentage who had both cats and dogs , $n(C \cap D)$ = 12%

Percentage who had neither cats nor dogs, $n(C \cup D)'$ =45%

Now:

Universal Set, $U = n(C)+n(D)-n(C \cap D)+n(C \cup D)'$

$100 = 40 + n(D)-12+45\\n(D)=100-73\\$Percentage of those who own dogs =27\%$

Therefore:

Number of Students who had dogs

=27% of 300

=81

3 0

3 years ago