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GenaCL600 [577]
3 years ago
7

4|x-2|-12 = 0 Absolute Value & Set in notation

Mathematics
2 answers:
Sphinxa [80]3 years ago
8 0

Answer:

x= 5 , x = -1

Step-by-step explanation:

4|x-2|=12

|x-2| = 3

x-2 = 3

x = 5

x-2 = -3

x= -1

Angelina_Jolie [31]3 years ago
7 0
4|x-2|-12=0
X1= -1 and X2= 5
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we are given

f(x)=2x^4-x^3+x-2

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

f(-1)=2(-1)^4-(-1)^3+(-1)-2

f(-1)=0

At x=1:

f(1)=2(1)^4-(1)^3+(1)-2

f(1)=0

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

f(0)=2(0)^4-(0)^3+(0)-2

f(0)=-2

At x=1:

f(1)=2(1)^4-(1)^3+(1)-2

f(1)=0

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

f(-2)=2(-2)^4-(-2)^3+(-2)-2

f(-2)=36

At x=-1:

f(-1)=2(-1)^4-(-1)^3+(-1)-2

f(-1)=0

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

f(-1)=2(-1)^4-(-1)^3+(-1)-2

f(-1)=0

At x=0:

f(0)=2(0)^4-(0)^3+(0)-2

f(0)=-2

so, this is FALSE



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xeze [42]

Answer:

b

Step-by-step explanation:

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