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GenaCL600 [577]
3 years ago
7

4|x-2|-12 = 0 Absolute Value & Set in notation

Mathematics
2 answers:
Sphinxa [80]3 years ago
8 0

Answer:

x= 5 , x = -1

Step-by-step explanation:

4|x-2|=12

|x-2| = 3

x-2 = 3

x = 5

x-2 = -3

x= -1

Angelina_Jolie [31]3 years ago
7 0
4|x-2|-12=0
X1= -1 and X2= 5
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Are you sure it is correct because for each one your just doubling the number. 2+2=4. 4+4=8. 8+8=16. I think its suppose to be 16+16= 32 and so on, but I may be wrong
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a student bought a juice pouch for $2.50 and 3 bags of chips. the total cost was $5.05 write and solve an equation to determine
Wittaler [7]

First, write it as an equation

2.50+3x=5.05

Next, subtract 2.50 from both sides

2.50-2.50+3x=5.05-2.50

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5 0
3 years ago
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given the following linear function sketch the graph of the function and find the domain and range. f(x)=-5x+4
velikii [3]

It's a linear function. We need only two points to sketch the graph.

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for x = 1 → y= -5(1) + 4 = -5 + 4 = -1 → (1, -1)

The domain and the range is the set of all real numbers.

5 0
3 years ago
Find the value of the expression x3−y3+x2+y2+3 by substituting x=−2 and y=1.
vaieri [72.5K]

\\ \sf\dashrightarrow x^3-y^3+x^2+y^2+3

\\ \sf\dashrightarrow (-2)^3-(1)^3+(-2)^2+(1)^2+3

\\ \sf\dashrightarrow -8-1+4+1+3

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Please help me with this question :)​
klio [65]

Answer:

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from this we can say

y: (-infinity,5/6) (5/6, infinity]

or, y does not exist from (-infinity,5/6)

and does exist from (5/6, infinity]

3 0
2 years ago
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