All categories

3 years ago

I need a proper answer please, thanks so much.

1 answer:

7 0

Start of by setting up the slope formula:
$\frac{y_2-y_1}{x_2-x_1} =slope$

We are given 2 coordinates and the slope
(-6,w)(-10,4)
slope:1/8

Label your coordinates:
(-6,w) and (-10,4)
x1,y1 x2-y2

Put these numbers into the formula
$\frac{4-w}{-10-(-6)} = \frac{1}{8}$

Simplify the current info given:
$\frac{4-w}{-4} = \frac{1}{8}$

Now you would be able to guess and check,

Final answer: w=9/2

You might be interested in

URGENT!!! 100PTS!!!

gavmur [86]

Answer:

112560

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

1 + 1 = 2????? and<br>2 + 2 = 4??????

Vilka [71]

No, 1+1= Fish, 2+2=window duhhh xD

jkjk, 1+1=2 and 2+2=4 haha

3 0

3 years ago

Read 2 more answers

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

<em>See attachment for result of 1-VarStats</em>

8 0

3 years ago

Mary has $311.75 to convert into yen. the currency exchange she is using charges a surcharge of 6% when converting currency. abo

Leona [35]

Mary will receive 1512.4931 more Yen if she makes her trade on the day with the most favorable exchange rate than that of the least favorable exchange rate.

<h3>What is the exchange rate?</h3>

It is the factor by which currency conversion of two countries is done.

The most Favorable day is Friday because the exchange rate on Friday is the highest.

So, Mary will receive on Friday= 311.75 x 92.7120 x 94/100

Mary will receive on Friday(a)=27168.788 Yen

The least Favorable day is Wednesday because the exchange rate on Wednesday is the least.

So, Mary will receive on Wednesday= 311.75 x 87.5507 x 94/100

So, Mary will receive on Wednesday(b)= 25,656.2949 Yen

Difference between (a) and (b) = 1512.4931 Yen

Hence, Mary will receive 1512.4931 more Yen if she makes her trade on the day with the most favorable exchange rate than if she makes her trade on the day with the least favorable exchange rate.

To get more about the exchange rate visit:

brainly.com/question/1366402

6 0

2 years ago

A person recently read that 84% of cat owners are women. How large a sample should the researcher take if she wishes to be 90% c

Lana71 [14]

Answer:

405

Step-by-step explanation:

To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.

$n=\frac{(z_{\frac{\alpha }{2} })^{2} *p*q }{E^2}$

The values that are given are p = 0.84 and E = 0.03.

You can solve for the critical value which is equal to the z-score of (1 - confidence level)/2. Use the calculator function of invNorm to find the z-score. The value will given with a negative sign, but you can ignore that.

(1 - 0.9) = 0.1/2 = 0.05

invNorm(0.05, 0, 1) = 1.645

You can also solve for q which is 1 - p. For this problem q = 1 - 0.84 = 0.16

Plug the values into the equation and solve for n.

$n =\frac{(1.645)^2*0.84*0.16}{(0.03)^2}\\n= 404.0997333$

Round up to the next number, giving you 405.

6 0

3 years ago