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3 years ago

15

Unit rate word problem,Bridget read a total of 48 books over 12 months.If Bridget has 68 books so far,how many month has she bee

n with her book club

1 answer:

SOVA2 [1]3 years ago

7 0

The correct answer is 17

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Whats 1/5 + -4 having trouble

garri49 [273]

1/5+ (-4) is the same as 1/5 - 4
1/5-20/5
-19/5

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2 years ago

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Sergio's internet provider charges its customers $9 per month plus 4¢ per minute of on-line usage. Sergio received a bill from t

Degger [83]

$81.40-$9.00=$72.40
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3 years ago

The quadratic function h(t) = -16t^2 + 120 represents the height of 120 feet. what is the height of the object after 1.5 seconds

Anettt [7]

Answer:

84 feet

Step-by-step explanation:

-16(1.5)^2+120=84

5 0

2 years ago

The southward translation of the rose garden is along which axis? What integer represents a change of four yards south?

Sphinxa [80]

Going south means you're going in the negative direction along the y axis

Going 4 yards south would be represented as -4 on the y axis number line (this is the vertical number line)

3 0

3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago