Let
be the set of all students in the <u>c</u>lassroom.
Let
and
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given




i. We can split up
into subsets of students that pass both physics and math
and those that pass only physics
. These sets are disjoint, so

ii. 9 students fails both subjects, so we find

By the inclusion/exclusion principle,

Using the result from part (i), we have

and so the probability of selecting a student from this set is

Answer:
I think it is 3.5
Step-by-step explanation:
8.5:250*100 =
(8.5*100):250 =
850:250 = 3.4
A Beards, Beards where a fashion choice back then, just like how wemon had black teeth and white painted faces!
C May be the answer sorry if it is wrong.
Part A:
There are 25 blocks for the length, and the length of each is 5.5 inches. 5.5x25=137.5
There are 9 blocks for the height, and each is 2.75 inches. 2.75x9=24.75
Since we're trying to find how much longer the length is to the width, we find the difference. 137.5-24.75=112.75
So part A answer is <em><u>112.75 (or 112¾)</u></em>
Part B:
We know the length is 137.5 and the height is 24.75. To find how many times longer the length is, we need to divide to see how many 24.75 can go into 137.5.
137.5÷24.75=5.55
So the answer to part B is <u><em>5.55. Given the context, the answer would probably be 5, because that's how many entire height can fit.</em></u>
<u><em /></u>
Sorry if it's wrong lol