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Ivanshal [37]
3 years ago
12

May I please get help in 7th grade math?

Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:

what

Step-by-step explanation:

what do you need help on?

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Sujan bought 16 pens for Rs256. how much would he have to pay for one pen he buys next time?<br>​
Elodia [21]

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3 years ago
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What is the equation of the line perpendicular to 2x – 3y = 6 that passes through the point (4, 1)?
san4es73 [151]

Answer:

2x + 3y = 14

100% sure final answer

7 0
4 years ago
Find the pattern and the next three terms<br><br> 2,3,5,7,11,13
kobusy [5.1K]

Answer:

the

Step-by-step explanation:

the pattern is of prime numbers and next three terms is 17,19,23 thank you

5 0
3 years ago
A building is 5 feet tall. the base of the ladder is 8 feet from the building. how tall must a ladder be to reach the top of the
iris [78.8K]

The ladder must be 9.4 ft to reach the top of the building

Here, we want to get the length of the ladder that will reach the top of the building

Firstly, we need a diagrammatic representation

We have this as;

As we can see, we have a right triangle with the hypotenuse being the length of the ladder

We simply will make use of Pythagoras' theorem which states that the square of the hypotenuse is equal to the sum of the squares of the two other sides

Thus, we have;

\begin{gathered} x^2=5^2+8^2 \\ x^2=\text{ 25 + 64} \\ x^2\text{ = 89} \\ x=\text{ }\sqrt[]{89} \\ x\text{ = 9.4 ft} \end{gathered}

5 0
2 years ago
Select the correct answer from each drop-down menu. The equation (y-2)^2/3^2 - (x-2)^2/4^2=1 represents a hyperbola whose foci a
aev [14]

Answer:

The foci are (2 , 7) and (2 , -3)

Step-by-step explanation:

* lets revise the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the y-axis is

  (y - k)²/a² - (x - h)²/b² = 1

- The coordinates of the vertices are ( h ± a , k )  

- The coordinates of the co-vertices are ( h , k ± b )

- The coordinates of the foci are (h , k ± c), where c² = a² + b²

* Now lets solve the problem

∵ The equation of the hyperbola of vertex (h , k) is

    (y - k)²/a² - (x - h)²/b² = 1

∵ The equation is (y - 2)²/3² - (x - 2)²/4² = 1

∴ k = 2 , h = 2 , a = 3 , b = 4

∵ The foci of it are (h , k + c) and (h , k - c)

- Lets find c from the equation c² = a² + b²

∵ a = 3

∴ a² = 3² = 9

∵ b = 4

∴ b² = 4² = 16

∴ c² = 9 + 16 = 25

∴ c = √25 =  5

- Lets find the foci

∵ The foci are (h , k + c) and (h , k - c)

∵ h = 2 , k = 2 , c = 5

∴ The foci are (2 , 2 + 5) and (2 , 2 - 5)

∴ The foci are (2 , 7) and (2 , -3)

5 0
4 years ago
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