The median number of cars for both distributions lies in the 20–30 interval and there were more than 40 cars in line more often on the weekend then the weekday.
<h3>What is mean and median ?</h3>
The arithmetic mean is found by adding the numbers and dividing the sum by the number of data in the list.
The median is the middle value in a list ordered from smallest to largest.
Given data:
Data A:
0 - 10 4
10 - 20 13
20 - 30 19
30 - 40 8
40 - 50 5
50 - 60 1
Data B:
0-10 12
10-20 20
20-30 14
30-40 3
40-50 1
Thus, the median number of cars for both distributions lies in the 20–30 interval and there were more than 40 cars in line more often on the weekend then the weekday.
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9514 1404 393
Answer:
(c) 1.649
Step-by-step explanation:
For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.
Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.
The area by trapezoidal integration is about 1.649 square units.
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In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.
Answer:
Step-by-step explanation: