Answer:
9) 844cm^2 10) 15,000in^3 11) 240cm^3 12) 480in^3
Step-by-step explanation:
9) A= 200 A=160 A=192 A=192 A=100
200+160= 360+192= 552+192= 744+100=844cm^2
for #9 i divided the figure into 5 parts and got the area of each one and added all of the totally areas to get the final answer
10) A= 20*30= 600*25= 15,000in^3
11) A= 2*5= 10*4= 40cm^2 (cheese) A= 40*6= 240cm^3
12) 12*10= 120*4= 480in^3
Answer:
600,000(1+0.03)^20 that’s your equation. use a calculator. remove decimals from your answer because its not possible
Answer:
28.) c.
29.) a and c.
30.) a.
y=3x/5 +18/5
b.
(-6, 0)
31.) y=x-4
Step-by-step explanation:
28.)
pounds is equal to the y value of a graph, while months is equal to the x value of the graph. slope is equal to y/x. Therefore, it is the slope.
29.) rearrange the equation to isolate the y value and then divide every equation by 2. you will then get y=4x+8. When you plug each of the points in, you will notice only a and c are true.
30.) a.
The line equation is: y=mx+b. First find the slope. You can do that with subtracting y values over dividing x values. You should get: 3-6/-1-4=3/5.
With this slope, plug in one of the points for the x and y values, and solve for b. I used the point (-1, 3) and got b=18/5
b.
For this, I found that 0= 3(-6)/5+18/5
31.) Find the slope by subtracting the y values over subtracting the x values. This should give you a slope of 1. After you find the slope, plug in your slope as m in the line equation: y=mx+b. Next, find a point in that plot and plug those in to find the y intercept (b). I chose (-2, -6) and (2, -2) and got a slope of -4. However, you can also see that when x=0, y=-4, so that could also be a nice shortcut.
Hope this helps!
Answer:
The angle bisector is construct.
Step-by-step explanation:
We used the geogebra.org site. We first constructed a large triangle with acute angles. Then from point A we made a semicircular section to its sides. At the intersection of the sides and the semicircular section, we construct two circles so that they intersect. Then from the point A we draw a line through the intersection of the circles and thus we obtain the bisector of the angle.
We repeat the same procedure for point B and for point C. In this way, we obtain a bisector for all angles of a triangle.
