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lina2011 [118]
4 years ago
6

Simplify 100y^3/98xy

Mathematics
1 answer:
kozerog [31]4 years ago
4 0
The answer is 50y^2/49x . hope I helped 
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Perform the following division: (–1/6) ÷ (–3/7) A. –7/18 B. 7/18 C. –3/42 D. 3/42
Crank

Answer:

B. 7/18

Step-by-step explanation:

(-1/6)/(-3/7)

= -1/6 * -7/3

= -1*-7/6*3

= 7/18

(pls give brainliest)

3 0
3 years ago
Read 2 more answers
3/4 (4x+8)=-12. Distributive property
Scrat [10]

Answer:

x = -6

Step-by-step explanation:

I'm assuming you're solving for x

3/4 (4x + 8) = -12

you distribute the 3/4 to 4x and 8 so

3/4 times 4x = 3x

3/4 times 8 = 6

now looks like

3x + 6 = -12

3x = -12 - 6

3x = -18

x = -6

7 0
3 years ago
Need to find the value of y
alexgriva [62]

Answer:

√55

Step-by-step explanation:

Notice that the small triangle in the bottom corner shares an angle with the overall triangle.  Also, they are both right triangles.  Therefore, they are similar triangles.

Notice that the large triangle at the top shares an angle with the overall triangle and is also a right triangle.  Therefore it is also similar to the overall triangle and the smaller triangle.

Writing a proportion between the small and large triangles:

y / 11 = 5 / y

y² = 55

y = √55

3 0
3 years ago
Find the indefinite integrals ​
Alexxx [7]

Answer:

Below in bold

Step-by-step explanation:

∫ dx / (x^2√(9-x^2))

Substitute x = 3sinu and dx = 3cosu du

then the √(9-x^2) = √( 9 - 9sin^2u) = 3 cos u  and u = arcsin(x/3)

= 3 ∫(csc^2 u du )/ 27

= 1/9 ∫(csc^2 u du

= -1/9 cot u

= -√9-x^2) / 9x.

4 0
3 years ago
A ​20-ft by ​the 40-ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway i
Jlenok [28]
<h3>Answer:  2 feet</h3>

========================================================

Explanation:

x = width of the walkway in feet

This is some positive real number.

The dimension of 20 feet bumps up to 20+2x when adding on x from both directions. Similarly, the 40 ft dimension becomes 40+2x

Refer to the diagram below.

The 20 ft by 40 ft pool is surrounded by a larger rectangle that is 20+2x ft by 40+2x ft

The pool itself is 20*40 = 800 sq ft. Add on the walkway area to get 800+256 = 1056 sq ft.

-----------

Area = length*width

1056 = (20+2x)*(40+2x)

1056 = 20*40 + 20*2x + 2x*40 + 2x*2x ... FOIL rule

1056 = 800 + 40x + 80x + 4x^2

0 = 4x^2 + 40x + 80x + 800 - 1056

0 = 4x^2 + 120x - 256

4x^2 + 120x -  256 = 0

4(x^2 + 30x - 64) = 0

x^2 + 30x - 64 = 0

Let's use the quadratic formula to finish solving for x.

Plug in a = 1, b = 30, c = -64

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-30\pm\sqrt{(30)^2-4(1)(-64)}}{2(1)}\\\\x = \frac{-30\pm\sqrt{1156}}{2}\\\\x = \frac{-30\pm34}{2}\\\\x = \frac{-30+34}{2} \ \text{ or } \ x = \frac{-30-34}{2}\\\\x = \frac{4}{2} \ \text{ or } \ x = \frac{-64}{2}\\\\x = 2 \ \text{ or } \ x = -32\\\\

Recall we made x be positive. This is because a negative walkway width does not make sense. This means we'll ignore x = -32.

The only practical solution is x = 2

Therefore, the walkway is <u>2 feet wide</u>

4 0
2 years ago
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