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Stels [109]
3 years ago
8

How many times greater is 7,000,000 than 70,000

Mathematics
1 answer:
Kryger [21]3 years ago
6 0
The answer is 100 times
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Whats 2+2 i dont know what it is
SOVA2 [1]

Answer:

4

Step-by-step explanation:

2+2=4

thanks:D

5 0
3 years ago
Read 2 more answers
1.20 x 10⁶<br><br>6.0 x 10⁵​
omeli [17]

Answer:

1.20 x 10^{6}=1,200,000\\\\6.0 x 10^{5}=600,000

Step-by-step explanation:

You move the decimal place over 6 times for the first equation and 5 for the second equation.

Hope this helps! Have a great day! :)

8 0
3 years ago
Solve for k.<br> 6k - 8 = 4K + 15
Brut [27]

Hi,

Answer:

k = \frac{23}{2}

Step-by-step explanation:

Subtract 4k from both sides

6k - 4k = 2k

2k - 8 = 15

Add 8 on both sides (you want to get rid of the 8 in order to leave the k alone)

2k = 23

k = 23/2

Have a good day!

4 0
3 years ago
Read 2 more answers
How many 20 degree angles does it take to make a full turn?
scoundrel [369]
There is 360* in a circle, so you would divide 360 by 20 to get 18. 
3 0
3 years ago
In the diagram below, AC and CB, AB and CD, and m(angle)A=33 degrees. Find M(angle)B
hoa [83]

Answer:

15°.

Step-by-step explanation:

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Have a good Day!

7 0
3 years ago
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