We know that
Perimeter=2AB+2AD=34 in-----> AB+AD=17-----> AB=17-AD-----> equation 1
MA=MD
MA²=AB²+(AD/2)²
for the triangle AMD
AD²=[MA²+MD²]----> AD²=2*[MA²]----> AD²=2*[AB²+(AD/2)²]---> equation 2
I substitute 1 in 2
AD²=2*[(17-AD)²+(AD/2)²]----> AD²=2*[289-34AD+AD²+0.25AD²]
AD²=578-68AD+2.50AD²--------> 1.50AD²-68AD+578
1.50AD²-68AD+578=0
using a graph tool to solve the quadratic equation
see the attached figure
AD1=11.33 in
AD2=34 in----------is not solution because (AB+AD=17)
Solution is AD=11.33 in
AB=17-11.33--------> 17-11.33-----> AB=5.67 in
the answer is
AD=11.33 in
<span>AB=5.67 in</span>
1. is 450ft, and #2. is 64ft.
Answer:
800 pounds.
Step-by-step explanation:
We have been given that an object that weighs 24 pounds on Mercury weighs approximately 80 pounds on Earth. A rock weighs 240 pounds on Mercury. We are asked to find the weight of rock on Earth.
We will use proportions to solve our given problem as proportions state that the ratio between two proportional quantities is equal.

Upon substituting our given value, we will get:




Therefore, the weight of rock on Earth would be approximately 800 pounds.
Answer:
3
Step-by-step explanation:
Points A and B lie on the horizontal line y = 1. The length of segment AB is then the difference of the x-coordinates of the points:
5 -2 = 3
The length of side AB is 3 units.