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3 years ago

Xm-2m if x=-2 and m=-3

Mathematics

1 answer:

swat323 years ago

3 0

The answer would be 12. (-2)(-3) = 6, then (2)(-3) is -6. 6-(-6) would be 6+6.

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Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3

Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

$f\left(x\right)=\sqrt{x^3-16x}$

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

$x^3-16x\ge 0$

as x³ - 16x ≥ 0

$\left(x+4\right)\left(x-4\right)\ge \:0$

Thus, identifying the intervals:

$-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4$

Thus,

The domain of the function f(x) is:

$x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}$

And the Least Value of the domain is -4.

3 0

3 years ago

3x- 4x + x<br> Like terms or not Like terms?

tester [92]

Answer:

like terms

Step-by-step explanation:

they all are terms that include the letter x

5 0

3 years ago

Read 2 more answers

PLZ HELP 35 POINTS

Alex787 [66]

Answer:

i think b im not sure

Step-by-step explanation:

6 0

3 years ago

Jo sold 132 mugs. One quarter of the mugs were small. The rest were large. How many small mugs did Jo sell? * 1 point

GarryVolchara [31]

Answer:

33 small mugs

Step-by-step explanation:

Given:

Total number of mugs sold by Jo = 132

One quarter of the mugs were small. The rest were large.

To find: Number of small mugs sold by Jo

Solution:

Number of small mugs sold by Jo = $\frac{1}{4}$ (Total number of mugs sold by Jo)

Therefore,

Number of small mugs sold by Jo $=\frac{1}{4}(132)=33$

3 0

3 years ago

Simplify.<br> Rewrite the expression in the form b^n<br><br> (b^3)^2

Alexxandr [17]

Step-by-step explanation:

$a^n={\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}$

<h2>METHOD 1.</h2>

$\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=\underbrace{b\cdot b\cdot b}_{3}\cdot\underbrace{b\cdot b\cdot b}_{3}=\underbrace{b\cdot b\cdot b\cdot b\cdot b\cdot b}_{6}=b^6$

<h2>METHOD 2.</h2>

$\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=b^{3+3}=b^6\qquad\text{used}\ a^n\cdot a^m=a^{n+m}$

<h2>METHOD 3.</h2>

$\left(b^3\right)^2=\left(\underbrace{b\cdot b\cdot b}_{3}\right)^2=b^2\cdot b^2\cdot b^2=b^{2+2+2}=b^6\\\text{used}\ (ab)^n=a^nb^n,\ a^n\cdot a^m=a^{n+m}$

<h2>METHOD 4.</h2>

$\left(b^3\right)^2=b^{3\cdot2}=b^6\qquad\text{used}\ \left(a^n\right)^m=a^{nm}$

5 0

3 years ago