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kompoz [17]
3 years ago
11

Find the domain of the function f(x)=

-16x}" alt="\sqrt{x^3-16x}" align="absmiddle" class="latex-formula"> . What is the least value of x in the domain?
Least Value=
Mathematics
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

f\left(x\right)=\sqrt{x^3-16x}

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

x^3-16x\ge 0

as x³ - 16x ≥ 0

\left(x+4\right)\left(x-4\right)\ge \:0

Thus, identifying the intervals:

-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4

Thus,

The domain of the function f(x) is:

x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}

And the Least Value of the domain is -4.

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What I the equation in standard form of the line that passes through the points(4,-8) and has a slope of 1/4
valentinak56 [21]

Answer:

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Step-by-step explanation:

The slope of the line equation = 1/4

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Now, by POINT SLOPE formula,

The line equation  with slope m  nad point (x0,y0) is given as:

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So, the line equation here is given as

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8 0
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