Answer:
See Explanation
Step-by-step explanation:
Required
Determine if a real life situation is a function or not
I will give 2 instances
(1) Students and their ID
The relationship is as follows:
Student 1 -----> ID-1
Student 2 -----> ID-2
Student 3 -----> ID-3
Student 4 -----> ID-4
---------
----
--
Student n -----> ID-n
The above is a function because every student has a unique student ID.
In fact, the relation is a one-on-one function because no two students will have the same ID
(2) People and their year of birth
The relationship is as follows:
Person 1 -----> 2000
Person 2 -----> 2001
Person 3 -----> 2002
Person 4 -----> 2001
---------
----
Person n -----> 2005
The above is not a function because there is a possibility that a more than one person will have the same year of birth.
Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property:
![\frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
- Trig Derivative:
![\frac{d}{dx} [cos(x)] = -sin(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcos%28x%29%5D%20%3D%20-sin%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>: g'(0) = 10sin(0)
- Evaluate Trig: g'(0) = 10(0)
- Multiply: g'(0) = 0
The answer to your question is -19
Answer:
x = 2; y = 3; z = 1
Step-by-step explanation:
For the first fertilizer (A) we can form the equation:
y + 2z = 5
For the second fertilizer (B) we can form the equation:
x + 2y + 5z = 13
For the third fertilizer (C) we can form the equation:
x + 2z = 4
solving simulteneously:
y = 5 - 2z
x = 4 -2z
Substituting (i) and (ii) into (2)
4 - 2z + 10 -4z + 5z = 13
14-z =13, therefore z = 1
substituting z into (i) and (ii)
y = 3
x = 2
Answer:
The area of the shaded region is 
Step-by-step explanation:
we know that
The area of the shaded region is equal to the area of the rectangle minus the area of the circle
The rectangle is a square
so

we have


assume

substitute the values

