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gladu [14]
3 years ago
13

A candidate for mayor plans to campaign at 5 shopping malls before the election. In how many different ways can the candidate sc

hedule the visits? Enter your answer as a whole number, such as 42.
Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

120 different ways

Step-by-step explanation:

For the first shopping mall being visited, the candidate has 5 options

Then, for the second mall being visited, there is only 4 options, as one mall was already visited.

Following this logic, there is 3 options for the third mall, 2 options for the fourth mall and 1 option for the last mall.

So the total number of ways that the visits can be scheduled is the product of all these options:

5*4*3*2*1 = 120 different ways

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iogann1982 [59]
The average value of a data set is equal to the sum of each entry divided by the number of entries. In this case, we have 5 scores, so we can find set up the following equation where x is the fifth score:

\dfrac{78+81+83+76+x}{5} = 81

Now solve for x:

78 + 81 + 83 + 76 + x = 81(5)

318 + x = 405

x = 87

The fifth score must be 87.
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For the differential equation dy/dt=ky, k is a constant, y(0)=24, and y(1)=18. What is the value of k?
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The equation is separable, so solving it is trivial:

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Answer:

Correct option: first one

Step-by-step explanation:

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