<span>Int var1 = 0b0001;
int var2 = 0b1111;
int results1 = var1 & var2;
int results2 = var1 | var2;
int results3 = var1 ^ var2;
int printit = results1 + results2 + results3;
what are the values for results1, results2, results3 and printit after executing the code?
notes:
1. faster responses will be obtained if your code is presented line by line (in a file) before posting.
2. please specify language, many languages use the same syntax but could have differences in interpretation
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Assuming Java as the language. C is similar.
</span><span><span>& bitwise AND &
^ </span><span>bitwise exclusive OR
</span><span>| bitwise inclusive OR
So
results1=var1&var2=0b0001&0b1111=0b0001
results2=var1|var2=0b0001&0b1111=0b1111
results3=var1^var2=0b0001&0b1111=0b1110
printit=results1+results2+results3=0b0001+0b1111+0b1110
=0b10000+0b1110
=0b11110
Note: by default, int has 4 signed bytes, ranging from decimal -2147483648 to +2147483647
</span></span>
Answer:
47.72% of students scored between 563 and 637 on the exam .
Step-by-step explanation:
The percentage of the students scored between 563 and 637 on the exam
= The percentage of the students scored lower than 637 on the exam -
the percentage of the students scored lower than 563 on the exam.
Since 563 is the mean score of students on the Statistics course, 50% of students scored lower than 563. that is P(x<563)=0.5
P(x<637)=P(z<z*) where z* is the z-statistic of the score 637.
z score can be calculated using the formula
z*=
where
- M is the mean score (563)
- s is the standard deviation of the score distribution (37)
Then z*=
=2
P(z<2)=0.9772, which means that 97.72% of students scored lower than 637 on the exam.
As a Result, 97.72%-50%=47.72% of students scored between 563 and 637 on the exam
The formula used to find the area<span> of a circlular </span>sector<span> - a pie-shaped </span>part of a circle<span>. ... </span>π<span>. 4. 2. ·. 86. 360. = 12.01. What the formulae are doing is taking the </span>area<span> of the whole ... So for example, if the</span>central angle<span> was 90°, then </span>the sector<span> would </span>have<span> an </span>area<span> equal to one ... r is the </span>radius<span> of the </span>circle<span>of which </span>the sector<span> is </span>part<span>.</span>
To solve for the missing steps, let's rewrite first the problem.
Given:
In a plane, line m is perpendicular to line t or m⟂t
line n is perpendicular to line t or n⟂t
Required:
Prove that line m and n are parallel lines
Solution:
We know that line t is the transversal of the lines m and n.
With reference to the figure above,
∠ 2 and ∠ 6 are right angles by definition of <u>perpendicular lines</u>. This states that if two lines are perpendicular with each other, they intersect at right angles.
So ∠ 2 ≅ ∠ 6. Since <u>corresponding</u> angles are congruent.
Therefore, line m and line n are parallel lines.
<span>
<em>ANSWERS: perpendicular lines, corresponding</em>
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