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3 years ago

Can you help me on number 3

Mathematics

1 answer:

katovenus [111]3 years ago

7 0

Answer:

it is 11

Step-by-step explanation:

if you add 15 and 13 you get 28.

39-28= 11

then you check your work

15+13=28+11=39

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The student government association at a certain college assigns a number to each student enrolled, puts the numbers in order, an

snow_tiger [21]

Answer: Systematic

Step-by-step explanation:

3 0

3 years ago

Harold collected data on the daily high temperature in two cities over a period of one week.

Misha Larkins [42]

Answer:

Correct choices are 1 and 4

Step-by-step explanation:

As per data given we have:

Median temperature is 75°F and 88°F
And the range from the median is 5° for both cities

This gives us lowest temperatures of:

75° -5° = 70° and 88° - 5°= 83° respectively

And high temperatures are:

75° + 5° = 80° and 88° + 5° = 93°

Answer choices based on above details:

Choice 1 - correct
Choice 2 - incorrect. Correct answer is 93°
Choice 3 - incorrect. Correct answer is 93° - 70° = 23°
Choice 4 - correct

3 0

3 years ago

Julianne opens a dance studio. Her start-up costs for the building, advertising, and supplies $52,000. Each day, she spends $650

Yuki888 [10]

The equation is: $960d-650d=52000$ and Julianne will begin making a profit after 168 days.

Explanation

Her total start-up cost is $52,000.

Each day, she spends $650 on operating costs (like utilities and wages) and she earns $960 per day from her students' lesson fees.

If the number of days to overcome the start-up cost is $d$ , then

the total operation cost spent in $d$ days $= \$650d$ and

the total students' lesson fees earned in $d$ days $= \$960d$

Part A: The equation to represent the situation will be: $960d-650d=52000$

Part B:  Julianne will begin making a profit when....

$960d-650d>52000\\ \\ 310d>52000\\ \\ d>\frac{52000}{310}\\ \\ d >167.741... \approx 168$

So, Julianne will begin making a profit after 168 days.

5 0

3 years ago

Which expressions are equivalent to 2 (three-fourths x + 7) minus 3 (one-half x minus 5)? Check all that apply.

Mariulka [41]

Answer:

$2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))$

$2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)$

Step-by-step explanation:

The original expression given in the text is

$2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)$ (1)

And we want to check to what other expressions is equivalent. First of all, we solve it by writing explicitely each term:

$\frac{3}{2}x+14-\frac{3}{2}x+15$ (2)

Let's verify each of the other expressions separately. For the first one:

$2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))$

We see that this is equivalent to expression (1), since the first half is identical, while in the second one, the combination "+-" can be simply written as "-", so we get

$2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)$

Which is equivalent to (1).

For the 2nd one:

$2(\frac{3}{4}x)+2(7)+3(\frac{1}{2}x)+3(-5)$

This is not equivalent. In fact, here we have applied the distributive property to each term: however, the 3rd and 4th term are not correct, because the (3) must be negative (-3), as in the original expression.

If we write it explicitely in fact, we get

$\frac{3}{2}x+14+\frac{3}{2}x-15$

Which is different from (2).

For the 3rd one:

$2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)$

This one is equivalent. In fact, here we have applied the distributive property correctly. By solvign each term we get:

$\frac{3}{2}x+14-\frac{3}{2}x+15$

8 0

3 years ago

Read 2 more answers

Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

3 0

3 years ago