Question

A factory produces some batteries daily. 7/8 of the batteries are packaged immediately. 2/3 of the

Answer 1

Answer:

$\[\frac{1}{24}\]$

Step-by-step explanation:

Let the total number of batteries produced daily be represented by x.

7/8 of the batteries are packaged immediately.

So the total number of packaged batteries = $\[\frac{7x}{8}\]$

Remaining batteries = $\[x-\frac{7x}{8}\]$

= $\[\frac{x}{8}\]$

Two third of the remaining batteries are sent to charity.

So the total number of batteries sent to charity= $\[\frac{2}{3} * \frac{x}{8}\]$

= $\[\frac{x}{12}\]$

Remaining batteries are faulty.

So the total number of faulty batteries = $\[\frac{x}{8} - \frac{x}{12}\]$

= $\[\frac{3x - 2x}{24}\]$

= $\[\frac{x}{24}\]$

So the faction of batteries which are faulty =

= $\[\frac{x}{24} \div x\]$

= $\[\frac{1}{24}\]$