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Alja [10]
3 years ago
15

The answer to 25. please

Mathematics
1 answer:
Oksana_A [137]3 years ago
4 0
14, finding the rate of change is simple,
142-128 = 14
156-142 = 14
170-156 = 14
184-170 = 14

14+14+14+14 = 56

There are 4 integers so divide by 4

56/4 = 14

so the answer is 14


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The area of a rectangular garden is given by the quadratic function: LaTeX: A\left(x\right)=-6x^2+105x-294A ( x ) = − 6 x 2 + 10
damaskus [11]

Answer:

Step-by-step explanation:

Domain= All real numbers. To get this answer i just plug the x-values into the quadratic formula to get the y-output.

Maximum area=1323/8

Range= y<= 1323/8

3 0
3 years ago
The permiter of a square must be less than 160 feet. What is the maximum length of a side in feet?
ale4655 [162]

Answer:

39 ft

Step-by-step explanation:

40 feet would have been if the perimeter was 160ft. so since it has to be less than 160 the maximum (whole number) length of a side would be 39.

3 0
3 years ago
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First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
2 years ago
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AlladinOne [14]

O is the midpoint so both sides FO and OG need to equal each other.

3x + 17 = 7x - 15

Subtract 3x from both sides:

17 = 4x -15

Add 15 to both sides:

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Divide both sides by 4:

x = 32/4

X = 8

Now you have the value of X, solve for the lengths:

FO = 3x +17 = 3(8) +17 = 24 +17 = 41

OG = 7x -15 = 7(8) -15 = 56-15 = 41

Total length would be 41 + 41 = 82

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Answer:

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If we are trying to find the 3rd term of this <em>specific </em>sequence, then we simply plug in 3 as n.

T(3) = (3)² + 4

T(3) = 9 + 4

T(3) = 13

However, this isn't proper notation for an arithmetic or geometric sequence.

8 0
3 years ago
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