The area of a trapezoid is found using the formula, A = ½ (a + b) h, where 'a' and 'b' are the bases (parallel sides) and 'h' is the height (the perpendicular distance between the bases) of the trapezoid.
Its already in simplest form= 81/100
If the two distance provided are the two legs, you are looking for the hypotenuse. Use the pyth. theorem.
a^2+b^2=c^2
c^2=5^2+12^2
c^2=25+144
c^2=169
c=13
answer: B
Solution,
y = -x-4......(i)
3x + y =- 16.......(ii)
Now,
Substituting the value of y in equation (ii)
or, 3x + (-x-4)= -16
or,3x - x - 4 = -16
or, 2x= -16 +4
or, x = -12/2
: x = -6
Then,
Substituting the value of x in (i) equation;
or,y= -(-6) - 4
or,y= 6 - 4
: y =2
Once, 14 divided by 16 equals 1 with a remainder of 2
