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den301095 [7]
3 years ago
11

A 15 pound bag of candy cost $9.99. How much does 1 pound of candy cost? How do you know? Make sure to show all work and answer

the question in a sentence.
Mathematics
2 answers:
Law Incorporation [45]3 years ago
5 0

All you would do is divide 9.99/15 to get how much one pound costs.

The answer would be around 66 or 67 cents.

9.99/15=.666

lorasvet [3.4K]3 years ago
5 0

If a 15 pound bag of candy costs $9.99, then you can use a proportion to find the answer of a 1 pound bag.

15/9.99 = 1/x

9.99 = 15x

9.99/15 = 0.666

1 pound bag of candy will cost 66 cents.

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A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at ​​ (−2,
Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.  

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}  

\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{64}=8

Now let us find distance between vertex B and vertex C.

\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{25}=5

Now let us find distance between vertex C and vertex D.

\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{64}=8

Now let us find distance between vertex D and vertex A.

\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}  

\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}    

\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}

\text{Distance between vertex D and vertex A}=\sqrt{25}=5

Now let us add all these distances to find the total distance walked by Jared.  

\text{Total distance walked by Jared}=8+5+8+5

\text{Total distance walked by Jared}=26  

Since we have been given that one unit on the grid equals 1 yard,   therefore, Jared walked a distance equal to 26 yards.  

3 0
3 years ago
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storchak [24]

Answer:

63/64

Step-by-step explanation:

cross multiplication

7*9=63

8*8= 64

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Answer:

Step-by-step explanation:

write a rule for the n th term of the geometric sequence for which a_1=11 and a_4=88

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