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nataly862011 [7]
4 years ago
13

A prism measures base 15cm. Height 100mm. Length 40cm. Calculate volume of prism cm3

Mathematics
1 answer:
soldi70 [24.7K]4 years ago
5 0
The volume of the prism depends on the shape of its base. Since you haven't mentioned whether the base is a triangle or a rectangle, I'll solve it both ways.

1- If the base is a rectangle:
volume = length x width x height = 15 x 10 x 40 = 6000 cm^3

2- If the base is a triangle:
volume = area of base x height = (0.5 x 15 x 40) x 10 = 3000 cm^3
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Can someone explain to me what prime numbers are?
Ket [755]
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<span>Example: </span>
<span>2 can only be divided by 1 and itself </span>
<span>3 can only be divided by 1 and itself. </span>

<span>4 however, can be divided by 1 or 2 or itself </span>

<span>1 is not a prime number since it is not greater than one.</span>
7 0
3 years ago
Read 2 more answers
Please anyone help please ASAP please
Alborosie

Answer:

60

Step-by-step explanation:

Using the triangle exterior theorem the two non adjacent interior angles add up to the adjacent exterior angle so 49+x=109, x=60

4 0
3 years ago
What is the value of the expression shown when n = 6?
IrinaK [193]

Answer:

8 less then the quotient of 42 and a number

a " quotient " is the result of division

(42 / n ) - 8.....when n = 6

(42/6) - 8 =

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Step-by-step explanation:

5 0
3 years ago
Suppose the germination periods, in days, for grass seed are normally distributed. If the population standard deviation is 3 day
KatRina [158]

Answer:

The minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean is 25.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

If the population standard deviation is 3 days, what minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean?

This is n when \sigma = 3, M = 1. So

M = z*\frac{\sigma}{\sqrt{n}}

1 = 1.645*\frac{3}{\sqrt{n}}

\sqrt{n} = 3*1.645

(\sqrt{n})^{2} = (3*1.645)^{2}

n = 24.3

Rouding up to the nearest integer, 25.

The minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean is 25.

4 0
3 years ago
What is the answer to this expression?
Zepler [3.9K]

Answer:

plug it into your calculator \frac{\sqrt{(-5)^{2}-4(2)(-1) } }{2(2)} and you get \frac{\sqrt{33} }{4} or 1.44 to 3 sf.

7 0
3 years ago
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