<img src="https://tex.z-dn.net/?f=2r%20%2B%206%20%2B%203r%20%3D%2031" id="TexFormula1" title="2r + 6 + 3r = 31" alt="2r + 6 + 3r

kogti [31]

3 years ago

= 31" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

horsena [70]3 years ago

6 0

Hello from MrBillDoesMath!

Answer:

r = 5

Discussion:

2r + 6 + 3r = 31 => (Given)

(2r + 3r) + 6 = 31 => (combine r terms). Subtract 6 from both sides

5r + 6 -6 = 31 - 6 = 25 =>

5r = 25 =>

r = 25/5 = 5

Regards,

MrB

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