Answer:
-2 radical 5 the second one
Multiplying both sides of a rational equation by a variable expression introduces the possibility of extraneous solutions. Therefore, we must check the solutions against the set of restrictions. If a solution is a restriction, then it is not part of the domain and is extraneous.
what’s the question being asked:
Answer:
Step-by-step explanation:
for 2.2 you would still have 5^2 in brackets still
same kind of error for 2.1