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Let
x-------> <span>the probability that a boy is chosen
B------> </span>number of boys in the debate team
G------> number of girls in the debate team<span>
we know that
B+G=20-----> G=20-B-----> equation 1
</span>probability that a boy is chosen=number of boys in the debate team/total of people
so
x=B/20-------> equation 2
t<span>he probability that a girl is chosen is 2/3 the probability that a boy is chosen
</span>probability that a girl is chosen=(2/3)*x
probability that a girl is chosen=G/20
(2/3)*x=G/20-----> equation 3
substitute equation 1 in equation 3
(2/3)*x=[20-B]/20----> equation 4
resolve the equations system
x=B/20
(2/3)*x=[20-B]/20
using a graph tool
see the attached figure
the solution is
x=0.6
B=12
G=20-12-----> G=8
number of boys in the debate team is 12
number of girls in the debate team is 8
the probability that a boy is chosen is 0.6 ----> 60%
the probability that a girl is chosen is 0.6*(2/3)----> 0.4---> 40%
the answer is
number of girls in the debate team is 8
x-------> <span>the probability that a boy is chosen
B------> </span>number of boys in the debate team
G------> number of girls in the debate team<span>
we know that
B+G=20-----> G=20-B-----> equation 1
</span>probability that a boy is chosen=number of boys in the debate team/total of people
so
x=B/20-------> equation 2
t<span>he probability that a girl is chosen is 2/3 the probability that a boy is chosen
</span>probability that a girl is chosen=(2/3)*x
probability that a girl is chosen=G/20
(2/3)*x=G/20-----> equation 3
substitute equation 1 in equation 3
(2/3)*x=[20-B]/20----> equation 4
resolve the equations system
x=B/20
(2/3)*x=[20-B]/20
using a graph tool
see the attached figure
the solution is
x=0.6
B=12
G=20-12-----> G=8
number of boys in the debate team is 12
number of girls in the debate team is 8
the probability that a boy is chosen is 0.6 ----> 60%
the probability that a girl is chosen is 0.6*(2/3)----> 0.4---> 40%
the answer is
number of girls in the debate team is 8
The depth of a river changes after a heavy rainstorm. Its depth, in feet, is modeled as a function of time, in hours
y is the depth in feet and x is the time in hours
From the table we can see that
In 9 hours, the depth is 18 feet
In 18 hours , the depth is 21 feet
(9,18 ) and (18,21)
Average rate of change =
=
=
=
the average rate of change for the depth of the river is feet per hour