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scoundrel [369]
3 years ago
6

Which equation could generate the curve in the graph below?y=3x^2-2x+1

Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0
If you are asking what is the graph of y = 3x^2 -2x+1.

Then, the attached file would be the answer.

To check, b^2 - 4(a)(c), for each equation and use these facts:

If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.

If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.

If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots. 

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3 years ago
There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Find the numbers.
Pani-rosa [81]

There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19

<h3><u>Solution:</u></h3>

Given that, There are two numbers whose sum is 64.  

Let the number be a and b in which a is bigger.

Then, a + b = 64 ------ eqn (1)

The larger number subtracted from 4 times the smaller number gives 31.  

4 x b – a = 31  

4b – a = 31 ----- eqn (2)

We have to find the numbers.

So, from eqn (2)

a = 4b – 31

Subatitute a in (1)

4b – 31 + b = 64

On solving we get

5b  = 64 + 31  

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b = 19

So, b = 19, then eqn 1

a + 19 = 64

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a = 64 – 19

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Hence, the two numbers are 45 and 19

3 0
3 years ago
−20≤59(F−32)≤−15 please i need help<br><br> v+8 &lt;3v+8 &lt;3 or −8v&lt;−40−8v&lt;−40<br><br> 6
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The answer is -148≤ F≤ -103!
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3 years ago
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