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scoundrel [369]
3 years ago
6

Which equation could generate the curve in the graph below?y=3x^2-2x+1

Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0
If you are asking what is the graph of y = 3x^2 -2x+1.

Then, the attached file would be the answer.

To check, b^2 - 4(a)(c), for each equation and use these facts:

If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.

If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.

If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots. 

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saul85 [17]
The answer is 350.
<em>
m= minutes</em>

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Plan 2:  23+0.09<em>m</em>

9+0.13<em>m</em> = 23+0.09<em>m</em>
-9               -9
0.13<em>m</em> = 14+0.09<em>m</em>
-0.09<em>m</em>        -0.09<em>m</em>
0.04<em>m</em>= 14
14÷0.04= 350
<em>m</em>= 350
3 0
3 years ago
Read 2 more answers
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kupik [55]
8x - amount of boys
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7x = 7 x 13= 91 

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4 0
3 years ago
The figure shown is a rhombus. A rhombus with diagonals is shown. The diagonals form 4 triangles. The measures of the angles are
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A

Step-by-step explanation:

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Hello,

7)  A∪C={1,2,3,4,5,7,9}

8) A∩B={2,4}

C'= complement of C ={2,4,6}

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3 years ago
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Answer:

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= 48/50

= 25

3 0
3 years ago
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