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2 years ago

Complete this equation 2 2/3 +4/5= 40/? + 12/? = ?/?

Mathematics

1 answer:

OlgaM077 [116]2 years ago

6 0

Answer:(7/8 - 4/5)^2 = 9

1600

= 0.005625

Step-by-step explanation:

Subtract: 7

- 4

= 7 · 5

8 · 5

- 4 · 8

5 · 8

= 35

- 32

= 35 - 32

= 3

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(8, 5) = 40. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 8 × 5 = 40. In the next intermediate step the fraction result cannot be further simplified by cancelling.

In words - seven eighths minus four fifths = three fortieths.

Exponentiation: the result of step No. 1 ^ 2 = (3

) ^ 2 = 32

402

= 9

1600

In words - three fortieths squared = nine one-thousand six-hundredths.

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If a student was randomly guessing while completing a 20 question multiple choice exam, what is the probability they would score

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----

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Step-by-step explanation:

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3 years ago

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2 years ago

According to the data, the mean quantitative score on a standardized test for female college-bound high school seniors was 500.

Sveta_85 [38]

Answer:

6.68% of the female college-bound high school seniors had scores above 575.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 50

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(scores above 575)

P(x > 575)

$P( x > 575) = P( z > \displaystyle\frac{575 - 500}{50}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 575) = 1 - 0.9332= 0.0668 = 6.68\%$

6.68% of the female college-bound high school seniors had scores above 575.

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3 years ago