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3 years ago

What integer is equivalent to 25 3/2

Mathematics

1 answer:

bonufazy [111]3 years ago

4 0

<span>26.5 the way it is written but it could be asking for multiplication?</span>

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I need help with #18,20,22 and 24. Please show your work and I'm really thankful for your help as soon as possible!

Artist 52 [7]

I'll start 18 and 22 for you, and you should then be able to do the rest on your own!

For 18, what we literally do is apply the distance formula for all the points and add them up. For B to C, we get the distance between them to be
sqrt((x1-x2)^2+(y1-y2)^2)=sqrt((0-4)^2+(3-(-1))^2)=sqrt((-4)^2+4^2)=sqrt(16+16)=sqrt(32). Repeat the process for C to E, E and F, and F to B then add the results up to get your answer!

For 22, since the area of a rectangle is length*width (we know given the right angles and that the opposite sides are equal in how long they are), we can multiply 2 perpendicular lines, for example, BC and CE to get sqrt(32)*sqrt(8)=16 as the area

4 0

3 years ago

What's 24 ten thousands renaming

almond37 [142]

The answer is 24,000

3 0

3 years ago

Read 2 more answers

Please help due today

elena-s [515]

It’s more likely that warren picks a shirt as there’s more shirts than pants. hope this helps!!

4 0

3 years ago

Stewart School has 178 computers. Grade 3 has 58 computers and flgrade 4 has 57 computers. What equations can be used to find ho

Ilya [14]

Answer: $x=58+57=115$

$y=178-115=63$

Step-by-step explanation:

Let x be the number of computers Grade 3 and grade 4 has and y be the numbers of computers the rest of school has.

Then, x= Grade 3 computers +Grade 4 computers.

$\Rightarrow\ x=58+57=115$

And y = Total computers - x

$\Rightarrow\ y=178-115=63$

Therefore, The equations can be used to find how many computers the rest of the school has.

$x=58+57=115$

$y=178-115=63$

7 0

4 years ago

PLEASE HELP WILL GIVE BRAINLIEST AND 20 POINTS

klio [65]

15 inches.

The side length of the base is 4. Find the surface area of the base only by squaring the side length - 4² - which is 16. The surface area of the base is 16 in².

The surface area of the entire pyramid can be found using this equation:

$SA = B + \frac{1}{2} nbl$

Where:
- SA is the surface area (136 square inches)
- B is the area of the base (16 square inches)
- n is the number of triangles (4, because it's a square pyramid)
- b is the base length (4 inches)
- l is the slant length

Note that we have many parts of this equation, and all we need is the slant length. So, let's format the equation with what we have:

$136 = 16 + \frac{1}{2} * 4 * 4 * l$

So then we want to solve for l, the slant height. So, start by subtracting 16 from each side. This would give us:

$120 = \frac{1}{2} * 4 * 4 * l$

Now, multiply both sides by 2 to get rid of the fraction:

$240 = 4 * 4 * l$

Finally, divide both sides by four, twice (divide by 16):

$15 = l$

So, we know that the slant height of this pyramid is 15 inches.

4 0

4 years ago