Question

Josephine wants to put a wallpaper border around the ceiling of her room. The dimensions are 10 9/12ft and 8 1/2ft How many feet of border does she need?

Answer 1

we know that

the perimeter of a rectangle is equal to

$P=2x+2y$

where

x--------> is the length side of the room

y--------> is the width side of the room

In this problem we have

$x=10\frac{9}{12}\ ft\\ \\y=8\frac{1}{2}\ ft$

Convert mixed number to an improper fractions

$x=10\frac{9}{12}\ ft=\frac{10*12+9}{12}=\frac{129}{12}\ ft$

$y=8\frac{1}{2}\ ft=\frac{8*2+1}{2}=\frac{17}{2}\ ft$

substitute the values in the formula of perimeter

$P=2(\frac{129}{12})+2(\frac{17}{2})$

$P=(\frac{129}{6})+17$

$P=(21.5+17)\ ft$

$P=38.5\ ft$

$P=38 \frac{1}{2}\ ft$

therefore

the answer is

$38 \frac{1}{2}\ ft$

Answer 2

The answer would be 38 1/2 feet