A parallelogram has consecutive vertices A (-2,0), P (0,-2) and C (2,4). Find the fourth vertex.
2 answers:
Let the fourth vertex be D(a,b) Now equate the midpoint of AC and PD. After equating you will find x=0 and y=6
One way to do this is to find the equations of the lines parallel to AP and PC which pass through the points C and A respectively . Then solve the 2 equations for x and y. equation of line parallel to AP y - y1 = m (x - x1) m = -(-2) / -2 = -1 point C is (2,4) y - 4 = -1(x - 2) y = -x + 6 equation (1) equation of the line parallel to pc:- slope m = 6/2 = 3 y - 0 = 3(x - (-2) y = 3x + 6 equation (2) solving (1) and (2):- - x + 6 = 3x + 6 x = 0 and y = 3(0) + 6 = 6 So the fourth vertex is at (0,6)
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