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bagirrra123 [75]
2 years ago
11

Answer 1a please and thank you

Mathematics
1 answer:
arlik [135]2 years ago
3 0

Answer:h

Step-by-step explanation:

j

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Alex
\frac{ x^2+6x-27 }{x-3} = \frac{ x^2+6x +3x-3x-27 }{x-3} = \frac{ x^2+9x-3x-27 }{x-3} = \\ \\ =\frac{ x(x +9 )-3(x+9) }{x-3} = \frac{ (x +9 ) (x-3) }{x-3} = x+9 \\ \\ \\ x-3\neq 0 \\x\neq 3\\D=R\setminus \left \{ 3 \right \}


4 0
2 years ago
Does anyone know the answer?
laila [671]

Answer:

a. θ = 30°

b. μ = √3 / 15 ≈ 0.115

Step-by-step explanation:

Draw a free body diagram for each scenario (see attached figure).  The body has four forces acting on it:

  • Weight pulling down
  • Normal force perpendicular to the incline
  • Applied force parallel up the incline
  • Friction force parallel to the incline

Remember that friction opposes the direction of motion.  So when the body is sliding up, friction points down the incline.  And when the body is sliding down, friction points up the incline.

Now apply Newton's second law to each scenario, first in the normal direction, then in the parallel direction.

For sliding up, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the incline:

∑F = ma

P₁ − f − mg sin θ = 0

P₁ − Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₁ − mgμ cos θ − mg sin θ = 0

Now for sliding down, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

And sum of the forces parallel to the incline:

∑F = ma

P₂ + f − mg sin θ = 0

P₂ + Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₂ + mgμ cos θ − mg sin θ = 0

We know that P₁ = 6 kg.wt, P₂ = 4 kg.wt, and mg = 10 kg.wt.

So we have two equations and two unknowns (μ and θ):

P₁ − mgμ cos θ − mg sin θ = 0

P₂ + mgμ cos θ − mg sin θ = 0

Let's start by adding the equations together:

P₁ + P₂ − 2 mg sin θ = 0

P₁ + P₂ = 2 mg sin θ

sin θ = (P₁ + P₂) / (2 mg)

Plugging in the values:

sin θ = (6 + 4) / (2 × 10)

sin θ = 1/2

θ = 30°

Now we can plug this into either equation and find μ.

P₁ − mgμ cos θ − mg sin θ = 0

6 − (10 cos 30°) μ − 10 sin 30° = 0

6 − 5√3 μ − 5 = 0

1 = 5√3 μ

μ = √3 / 15

μ ≈ 0.115

6 0
3 years ago
Trigonometry problem help please and thank you find angle wxz photo of problem is attached ​
Ksenya-84 [330]

Answer:

wxz = 25°

Step-by-step explanation:

way = 90

zxy = 65

So wxz = 25

Hope it helps you

5 0
2 years ago
7y=28, do I add, subtract, divide, or multiply each side
myrzilka [38]

Steps to solve:

7y = 28

~Divide 7 to both sides

7y/7 = 28/7

~Simplify

y = 4

Best of Luck!

5 0
3 years ago
Read 2 more answers
Number of
sergejj [24]

Answer:

45

Step-by-step explanation:

u add

7 0
3 years ago
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