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love history [14]

4 years ago

13

Show the ratios are equivalent by simplifying any 4 of them.

1 answer:

aliya0001 [1]4 years ago

4 0

When simplified all of them equal 3/1. They are asking you to just chose 4 of them. Hope that helps!

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Can someone help me with this math qt

FinnZ [79.3K]

Answer: 15

first find 1% of 48

it will be 48/100 = 0.48

now to find 29% multiply 1% with 29

it will 29*(.48) = 13.92

most close to 14. Also Close to 15.

That's all easiest way to solve such question.

3 0

3 years ago

Help me please if you can

zheka24 [161]

Answer:

perimeter = 1 3/4

Step-by-step explanation:

1. 3/4 x 2 because there are two sides with the fraction 3/4. 3/4 x 2 is 1 1/2

2. 1/8 x 2 because there are two sides with the fraction 1/8. 1/8 x 2 is 1/4

3. 1 1/2 + 1/4 = <u>1 3/4</u>

8 0

3 years ago

What must be true about the average rate of change between any two points on the graph of an increasing function?

frez [133]

Are there options to choose from?

4 0

3 years ago

True or false: the equation tan^2x+1=sec^2x

zhenek [66]

ANSWER

True

EXPLANATION

The given trigonometric equation is:

${ \tan}^{2} x + 1 = { \sec}^{2} x$

We take the LHS and simplify to arrive at the RHS.

${ \tan}^{2} x + 1 = \frac{{ \sin}^{2} x}{{ \cos}^{2} x} + 1$

Collect LCM on the right hand side to get;

${ \tan}^{2} x + 1 = \frac{{ \sin}^{2} x + {\cos}^{2} x}{{ \cos}^{2} x}$

This implies that

${ \tan}^{2} x + 1 = \frac{1}{{ \cos}^{2} x} .$

${ \tan}^{2} x + 1 = {( \frac{1}{ \cos(x) }) }^{2}$

${ \tan}^{2} x + 1 = { \sec}^{2} x$

This identity has been verified .Therefore the correct answer is true.

3 0

3 years ago

Which of the following is not equal to sin⁡(-230°)?

xenn [34]

From trigonometry we know that:

if $sin(\theta)=sin(\alpha)$

then, $\theta=n\pi+(-1)^n\alpha$ (where $n$ is an integer)

This can be rewritten in degrees as:

$\theta=n(180^{\circ})+(-1)^n\alpha$ .............(Equation 1)

Now, in our case, $\alpha=-230^{\circ}$

Therefore, (Equation 1) can be written as:

$\theta=n(180^{\circ})+(-1)^n(-230^{\circ})$ ..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of $\theta$ that match.

For n=2, (Equation 2) gives us: $\theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}$ .

Thus, $sin(230^{\circ})=sin(130^{\circ})$

Now, we know that: $-sin(-50^{\circ})=sin(50^{\circ})$

Let n=-1, then:

$\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}$

Thus, $sin(-230^{\circ})=-sin(-50^{\circ})$

Likewise, $sin(-230^{\circ})=sin(50^{\circ})$

Only the last option $sin(-50^{\circ})$ will never match $sin(-230^{\circ})$ because no integral value of $n$ will ever give $\theta=-50^{\circ}$

Thus the last option is the correct option.

3 0

3 years ago

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