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Ainat [17]
2 years ago
7

1/2x + 1/3y = 5 1/4x + y = 10

Mathematics
2 answers:
Pavel [41]2 years ago
8 0
The answer for your question is (x,y)=(4,9)
Sunny_sXe [5.5K]2 years ago
5 0
(x,y) (4,9) is the answer
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Please help me asappp! I'll give brainlest and points! ​
antiseptic1488 [7]

Answer:

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4 0
2 years ago
Read 2 more answers
On december 1, jonas jewelry wholesale center started with an inventory of 1,000 watches. shipments of 168, 231, and 411 were se
denis-greek [22]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Total watches in an inventory = 1000

Number of shipments sent out = 168, 231, 411

So, Remaining inventory of watches would be :

1000-(168+231+411)\\\\=1000-810\\\\=190

New receipts = 21, 145 and 11

So, Number of watches on hand becomes :

190+(21+145+11)\\\\=367

Hence, Third option is correct.

5 0
3 years ago
Solve 7 3/4- 5 5/4=
Kaylis [27]

Hey!

----------------------------------------------

Solution:

(5/4 = 1 1/4) and (1 1/4 + 6 = 6 1/4)

= 7 3/4 - 6 1/4 (5/4 = 1 1/4)

= 1 2/4 or 1 1/2

----------------------------------------------

Answer:

1 2/4 or 1 1/2

----------------------------------------------

Hope This Helped! Good Luck!

8 0
3 years ago
Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −
crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

  • \Delta = 150^2 - 4(-3)(-1200) = 8100
  • x_1 = \frac{-150 + \sqrt{8100}}{-6}
  • x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

  • \Delta = 150^2 - 4(-3)(-1800) = 900
  • x_1 = \frac{-150 + \sqrt{900}}{-6}
  • x_2 = \frac{-150 - \sqrt{900}}{-6} = 30

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0
1 year ago
Please help me!!! It’s due Thursday
timama [110]
That should be the answers

5 0
2 years ago
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