(2,2)
(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2
If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
The answer is 90%. Because 10% love math you subtract 100
Answer:
aₙ= 4n+11
Step-by-step explanation:
the sequence 15, 19, 23, 27
is AP with the first term 15 and
the common difference 19-15=23-19=27-23= 4
aₙ= a₁+(n-1)d
aₙ= 15+(n-1)*4= 15+4n- 4= 4n+11
aₙ= 4n+11