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Len [333]
3 years ago
8

Determine whether the improper integral converges or diverges, and find the value if it converges.

Mathematics
1 answer:
salantis [7]3 years ago
7 0

Answer:

Integral will be diverging in nature

Step-by-step explanation:

We have given integral \int_{5}^{\infty}\frac{3}{2}x^2dx

Now after solving the integral

[\frac{3}{2}\frac{x^3}{3}] limit from 5 to infinite

So [\frac{3}{2}\frac{\infty^3}{3}]-[\frac{3}{2}\times \frac{5^3}{3}]=\infty

As after solving integral we got infinite value so integral will be diverging in nature

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Calculate the perimeter of the following parallelogram:<br> 10 in<br> 4 in<br> 3 in
Furkat [3]
3 because when you catch
5 0
3 years ago
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Janelle subtracts -4 from a number. The result is -2. What is the number?0
kicyunya [14]

Answer:

-6

Step-by-step explanation:

? - (-4) = -2

? + 4 = -2

-6 + 4 = -2

Your Answer will be -6

Hope that helps!

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3 years ago
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I need to know 7 divided by 4/5 =
Basile [38]

Answer:

8.75 or 8 3/4

Step-by-step explanation:7

   

The numbers in 7 divided by 4/5 are labeled below:

7 = whole number

4 = numerator

5 = denominator

To make it a fraction form answer, you multiply the whole number by the denominator and make the result the new numerator. The old numerator becomes the new denominator:

7 x 5

4

 =    

35

4

Thus, the answer to 7 divided by 4/5 in fraction form is:

35

4

To make the answer to 7 divided by 4/5 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

35 / 4 = 8.75

The answer is rounded to the nearest two decimal points if necessary.

35/4 is an improper fraction and should be written as 8 3/4.

3 0
3 years ago
Write an equation to represent the relationship between red paint, r, and yellow paint, y, in each batch.​
Murljashka [212]

Answer:

not sure if that is the one I can answer

7 0
3 years ago
(1 point) The effectiveness of a new bug repellent is tested on 18 subjects for a 10 hour period. Based on the number and locati
jolli1 [7]

Answer:    

z=1.59

If we compare the p value and the significance level given \alpha=0.025 we see that p_v>\alpha so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.    

Step-by-step explanation:    

1) Data given and notation    

\bar X=0.92 represent the mean effectiveness of a new bug repellent for the sample    

\sigma=0.08 represent the population standard deviation for the sample    

n=18 sample size    

\mu_o =0.89 represent the value that we want to test  

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to determine if the mean repellency of the new bug repellent is greater than 89% or 0.89, the system of hypothesis would be:    

Null hypothesis:\mu \leq 0.89    

Alternative hypothesis:\mu > 0.89    

We don't know the population deviation, and the sample size <30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{0.92-0.89}{\frac{0.08}{\sqrt{18}}}=1.59    

Calculate the P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

Since is a one-side upper test the p value would be:    

p_v =P(t_{17}>1.59)=0.065

In Excel we can use the following formula to find the p value "=1-T.DIST(1.59;17;TRUE)"  

Conclusion    

If we compare the p value and the significance level given \alpha=0.025 we see that p_v>\alpha so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.    

6 0
4 years ago
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