Question

Determine whether the improper integral converges or diverges, and find the value if it converges.

Answer 1

Answer:

Integral will be diverging in nature

Step-by-step explanation:

We have given integral $\int_{5}^{\infty}\frac{3}{2}x^2dx$

Now after solving the integral

$[\frac{3}{2}\frac{x^3}{3}]$ limit from 5 to infinite

So $[\frac{3}{2}\frac{\infty^3}{3}]-[\frac{3}{2}\times \frac{5^3}{3}]=\infty$

As after solving integral we got infinite value so integral will be diverging in nature