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Len [333]
3 years ago
8

Determine whether the improper integral converges or diverges, and find the value if it converges.

Mathematics
1 answer:
salantis [7]3 years ago
7 0

Answer:

Integral will be diverging in nature

Step-by-step explanation:

We have given integral \int_{5}^{\infty}\frac{3}{2}x^2dx

Now after solving the integral

[\frac{3}{2}\frac{x^3}{3}] limit from 5 to infinite

So [\frac{3}{2}\frac{\infty^3}{3}]-[\frac{3}{2}\times \frac{5^3}{3}]=\infty

As after solving integral we got infinite value so integral will be diverging in nature

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Answer:

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Step-by-step explanation:

Using,

R/R' = 2ᵃ/ᵇ------------------ Equation 1

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2ᵃ = 187061.26

Taking the logarithm of both side,

Log2ᵃ = Log(187061.26)

⇒ a = log(187061.26)/log2

a = 8.272/0.301

a = 27.5 minutes

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