Let us start with the unknown. Let us give one of the base angles the
value of x. The other base angle is also x since both the base angles in
an isosceles triangle will be equal. The remaining angle is 40 more
than three times one of the base angles.It is 3x + 40. Here we get the
equation
x+x+3x+40=180
5x + 40 = 180
5x = 180 - 40 = 140
Therefore x = 140/5 = 28
So the angles are 28, 28 and 124.
The third angle is 3 times 28 + 40 = 84 + 40 = 124.
It takes 4.3 seconds for the rocket to return to earth.
The equation is:

where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:

We will use the quadratic formula to solve this. The quadratic formula is:

Plugging in our information we have:

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
Solve for "y" and you get y=3x/2-2 and the equation for a line is y= mx+b, I mean the slope is the number which companion the "x" in the line equation, so the slope in your problem is 3/2
The greatest common multiple is 8m, so this means that you can factor it out to:
=8m(3n+4)
=(8m•3n)+(8m•4)
=(24mn)+(32m)
=24mn+32m
The answer is option 2.