Question

The sum of four consecutive odd integers is –72. Write an equation to model this situation, and find the values of the four integers. A. n – (n + 2) – (n + 4) – (n + 6) = –72; n = –20; n + 2 = –18; n + 4 = –16; n + 6 = –14 B. n + (n – 2) + (n – 4) + (n – 6) = –72; n = – 21; n – 2 = –23; n – 4 = –25; n – 6 = – 27 C. n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –23; n + 4 = –25; n + 6 = –27 D. n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –19; n + 4 = –17; n + 6 = –15

Answer 1

Answer:

D. $n + n + 2 + n + 4 + n + 6 = -72; n = -21; n + 2 = -19; n + 4 = -17;n + 6=-15$

Step-by-step explanation:

Given:

The sum of four consecutive odd integers is -72.

Let the 4 consecutive odd integers be $n,n+2,n+4,\textrm{ and }n+6$

Now, as per question,

$n + (n + 2) + (n + 4) + (n + 6) = -72\\n+n+n+n+2+4+6=-72\\4n+12=-72\\4n=-72-12\\4n=-84\\n=-\frac{84}{4}=-21$

Therefore, the consecutive integers are:

$n=-21\\n+2=-21+2=-19\\n+4=-21+4=-17\\n+6=-21+6=-15$

Hence, the correct option is option D.