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adell [148]
3 years ago
12

Quanto é três x ao quadrado menos sete x mais dois e igual a zero ?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0
3x² - 7 x 2 ? É isso ? 
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Please help, this Math 1
Zolol [24]

Answer:

b

Step-by-step explanation:

not sure but i think thats the answer since 36.9/30 =1.23

6 0
4 years ago
What is the equation<br>​
slava [35]

Answer:

B. (x+1)^2+(y-2)^2=9

Step-by-step explanation:

The given circle is centered at  (-1,2) and has radius 3 units.

The equation is given by

(x-a)^2+(y-b)^2=r^2

where (a,b) is the center and r is the radius.

We substitute the values to obtain;

(x--1)^2+(y-2)^2=3^2

(x+1)^2+(y-2)^2=9

8 0
3 years ago
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Rudik [331]
He should change the coefficient 5
4 0
3 years ago
CAN SOMEONE HELP ME PLEASE ASAP!
nexus9112 [7]

Answer:

2 and 3

Step-by-step explanation:

20/12 = 1.6666666

15/9 = 1.6666666

6 0
3 years ago
A rare form of malignant tumor occurs in 11 children in a​ million, so its probability is 0.000011. Four cases of this tumor occ
Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

\lambda=r*t=0.000011*13,280=0.14608

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990

c) The probability of more than one case is:

P(k>1)=1-P(k\leq 1)=1-0.990=0.010

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0
3 years ago
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