Quanto é três x ao quadrado menos sete x mais dois e igual a zero ?

3680 x 4 equals what

allochka39001 [22]

14720 is answer. or product

7 0

3 years ago

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Divide.round your answer to the nearest hundredth 1divide 3

Sonbull [250]

Answer:

.33

Step-by-step explanation:

Hey there!

1 / 3

= .333333333

.33 rounded to the nearest hundredth

Hope this helps :)

3 0

2 years ago

Trapezoids and kites hw

miskamm [114]

Answer:

m<C = 101°

m<E = 46°

Step-by-step explanation:

*This was the only problem I could figure out so I'm sorry*

C equals 101° b/c 1/2 a circle angle equals 180° which is the line. Angle F and Angle C are corresponding interior angles (same side angles) so if both of them together should equal 180. 180 - 79 (<F) = 101 (<C).

You do the same thing to find Angle E b/c it's corresponding interior angles to Angle D.

I hope you understand this explanation

4 0

2 years ago

The mean is 10 which team will have the greatest MAD?

lara31 [8.8K]

answer: Larger the MAD tells us that the ages of swimmer are far from the mean age. Thus means is not a relevant indicator for the data.

explonation:

We know that the mean absolute deviation (MAD) helps to know whether the mean of a data is a worthy indicator for the data values.

The larger the MAD tells us the values are spread out far from the mean .

Also, larger the MAD makes the mean less worthy as an indicator of the data elements within the data set.

6 0

3 years ago

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What is the equation of the quadratic graph with a focus of (6, 0) and a directrix of y = −10 ?

Mademuasel [1]

Answer:

$(x-6)^{2}=20(y+5)^{2}$

Step-by-step explanation:

The standard for for the equation of a parabola is $(x-h)^{2}=4p(y-k)$

The focus is given as $(h, k+p)$

The directrix is given by $y=k-p$

Comparing focus given as $(6,0)$ to formula of focus $(h,k+p)$ , we see that $h=6$ and $k+p=0$
Comparing directrix given as $y=-10$ to formula of directrix $y=k-p$ , we can write $k-p=-10$

We can use the two system of equations [ $k+p=0$ and $k-p=-10$ ] to solve for $k$ and $p$ .

Adding the two equations gives us:

$2k=-10\\k=\frac{-10}{2}\\k=-5$

Using this value of $k$ , we can find $p$ by plugging this value in either equation. Let's put it in Equation 1. We have:

$k-p=-10\\-5-p=-10\\-5+10=p\\p=5$

Now, that we know $h=6$ , $k=-5$ , and $p=5$ , we can plug these values in the standard form equation to figure out the parabola's equation. Doing so and rearranging gives us:

$(x-6)^{2}=4(5)(y-(-5))^{2}\\(x-6)^{2}=20(y+5)^{2}\\$

This is the equation of the parabola with focus $(6,0)$ and directrix $y=-10$

3 0

3 years ago

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