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fenix001 [56]
3 years ago
10

[02.05] Solve for x: −3x + 3 < 6

Mathematics
2 answers:
NeX [460]3 years ago
8 0
-3x+3<6
minus 3 both sides
-3x<3
divide both sides by -3, don't forget to flip sign
x>-1
Luba_88 [7]3 years ago
4 0

Answer:

x>-1

Step-by-step explanation:

The given inequality is -3x+3

Subtract 3 to both sides of the inequality

-3x

Now, divide both sides by -3. Whenever, we divide/multiply  both sides by a negative number then the inequality sign gets reversed. Thus, we have

\frac{-3x}{-3}>\frac{3}{-3}\\\\x>-1

Hence, the solution is x>-1

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Use the compound amount formula:

A = P(1+r)^t

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Perimeter of a pentagon is 120cm what is the length of one of the sides
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Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

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Find the equation of the line tangent to the function at the given point f(x)=5x^2 at x=10
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