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Ulleksa [173]
3 years ago
12

Tony had a certain number of stamps that were each worth $0.15. He misplaced 7 stamps. He found that the total value of his stam

p collection was now $5.55.
Write an equation to represent the value of his stamp collection in terms of the number of stamps, s, that he had originally, and find the value of s.
Mathematics
1 answer:
erica [24]3 years ago
6 0
The Value Of S Is 100 or $1.00 or if you add it with the stamp collection then it'll be $6.55. 
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A jewellry shop sells 240 necklaces in a month
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Answer:

Ratio is 1:3

Step-by-step explanation:

Given that a jewellery shop sells 240 necklaces in a month. 180 were sold via the shops website, the rest were sold in a high street shop.

We have to work out the ratio for online sales to shop sales

Total sales .. 240

Shop sale .. 180

Online sa .. 60

Hence ratio for online sales:shop sales

5 0
3 years ago
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Name and describe the methods for determining a marketing budget.
Mekhanik [1.2K]

Answer: There are several ways in which we can determine our marketing budget. Some of these are given below:

<u><em>1. Percentage of revenues:</em></u>

Under this method we usually  take a fixed percentage of our revenues and further allocating this amount for marketing. We will choose the percentage that works best for us.

<u><em>2. Percentage of net sales:</em></u>

This method determines our marketing budget as a fraction of our net sales. This method will take a lot of trial and error to find the percentage that works well for our company.

<u><em>3. Industry specific:</em></u>

Nowadays, industries have specific projections as to the amount they will need to spend on marketing . The best way to get these numbers is to find a firm that represents our industry and ask them to provide us with averages. We can then refine the actual costs.

<em><u>4. Objective/task oriented </u></em>

This is model that works by setting out goals, planning out the tasks and then estimating the cost for all of these tasks. It works greatly for firms who have a immense knowledge about measurements and information of their business processes.

4 0
3 years ago
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4 0
3 years ago
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Computer keyboard failures are due to faulty electrical connects (12%) or mechanical defects (88%). Mechanical defects are relat
anzhelika [568]

Answer:

(c) Probability that a failure is due to loose keys = 0.2376

(d) Probability that a failure is due to improperly connected or poorly welded wires = 0.078

Step-by-step explanation:

The Whole probability scenario is given for Computer Keyboard failures.

(a) Let F be the event of failure due to faulty electrical connects, P(F) = 0.12

 M be the event of failure due to mechanical defects, P(M) = 0.88

 LK be the event of mechanical defect due to loose keys, P(LK/M) = 0.27

 IA be the event of mechanical defect due to improper assembly, P(IA/M)   =0.73

 DW be the event of electrical connects due to defective wires,P(DW/F) = 0.35

 IC be the event of electrical connects due to improper connections,

  P(IC/F) = 0.13 .

PWW be the event of electrical connects due to poorly welded wires,

  P(PWW/F) = 0.52

(b)                                     <u> </u><u>Keyboard failures</u>

<h2>                              /               \</h2>

           <u> </u><u> Faulty electrical connects   </u>            <u>Mechanical Defects </u>          

                      P(F) = 0.12                                             P(M) = 0.88

<h2>        /            |             \                  /            \</h2>

<u><em>Defective wires</em></u>  <u><em>Improper</em></u>        <u><em>Poorly</em></u>                  <u><em>Loose Keys</em></u>      <u><em>Improper</em></u><em> </em>

P(DW/F)=0.35   <u><em>Connections</em></u>   <u><em>Welded wires</em></u>      P(LK/M)=0.27   <em> </em><u><em>Assembly</em></u>

                           P(IC/F)=0.13     P(PWW/F)=0.52                            P(IA/M)=0.73              

This is the required tree diagram.

(c) Probability that a failure is due to loose keys is given by:

  P(LK) =P(LK/M) * P(M) {This means mechanical failure is due to loose  

                                               keys}

    P(LK) = 0.27 * 0.88 = 0.2376 .

(d) Probability that a failure is due to improperly connected or poorly welded

     wires is given by P(IC \bigcup PWW) ;

 P(IC \bigcup PWW) = P(IC) + P(PWW) - P(IC \bigcap PWW) { Here P(IC \bigcap PWW) = 0 }

 P(IC) = P(IC/F) * P(F)  = 0.13 * 0.12 = 0.0156

 P(PWW) = P(PWW/F) * P(F) = 0.52 * 0.13 = 0.0676

Therefore, P(IC \bigcup PWW) = 0.0156 + 0.0676 - 0 = 0.078 .

8 0
3 years ago
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