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Brrunno [24]
3 years ago
9

HELP I WILL MARK BRAINLIEST!!!

Mathematics
1 answer:
MrMuchimi3 years ago
8 0

Answer:

17.7 as the actual gas mileage recorded is 12 mpg.

Step-by-step explanation:

You might be interested in
The tables show proportional relationships. Find the constant of
SpyIntel [72]

Answer:

If the ratio of one variable to the other is constant, then the two variables have a proportional relationship,  

If x and y have a proportional relationship, the constant of proportionality is the ratio of y to x.

In this section, you will learn, how to find the constant of proportionality from a table which contains the values of x and y.

Step-by-step explanation:

I hope that helps, I'm so sorry if it doesn't

7 0
3 years ago
(6x-5y+4)dy+(y-2x-1)dx=0​
Len [333]

(6<em>x</em> - 5<em>y</em> + 4) d<em>y</em> + (<em>y</em> - 2<em>x</em> - 1) d<em>x</em> = 0

(6<em>x</em> - 5<em>y</em> + 4) d<em>y</em> = (2<em>x</em> - <em>y</em> + 1) d<em>x</em>

d<em>y</em>/d<em>x</em> = (2<em>x</em> - <em>y</em> + 1) / (6<em>x</em> - 5<em>y</em> + 4)

Let <em>X</em> = <em>x</em> - <em>a</em> and <em>Y</em> = <em>y</em> - <em>b</em>. We want to find constants <em>a</em> and <em>b</em> such that

d<em>Y</em>/d<em>X</em> = (a rational function)

where the numerator and denominator on the right side are free of constant terms. Substituting <em>x</em> and <em>y</em> in the equation, we have

d<em>Y</em>/d<em>X</em> = (2 (<em>X</em> + <em>a</em>) - (<em>Y</em> + <em>b</em>) + 1) / (6 (<em>X</em> + <em>a</em>) - 5 (<em>Y</em> + <em>b</em>) + 4)

d<em>Y</em>/d<em>X</em> = (2<em>X</em> - <em>Y</em> + 2<em>a</em> - <em>b</em> + 1) / (6<em>X</em> - 5<em>Y</em> + 6<em>a</em> - 5<em>b</em> + 4)

Then we solve for <em>a</em> and <em>b</em> in the system,

2<em>a</em> - <em>b</em> + 1 = 0

6<em>a</em> - 5<em>b</em> + 4 = 0

==>   <em>a</em> = -1/4 and <em>b</em> = 1/2

With these constants, the equation reduces to

d<em>Y</em>/d<em>X</em> = (2<em>X</em> - <em>Y</em>) / (6<em>X</em> - 5<em>Y</em>)

Now substitute <em>Y</em> = <em>VX</em> and d<em>Y</em>/d<em>X</em> = <em>X</em> d<em>V</em>/d<em>X</em> + <em>V</em> :

<em>X</em> d<em>V</em>/d<em>X</em> + <em>V</em> = (2<em>X</em> - <em>VX</em>) / (6<em>X</em> - 5<em>VX</em>)

The equation becomes separable after some simplification:

<em>X</em> d<em>V</em>/d<em>X</em> + <em>V</em> = (2 - <em>V</em>) / (6 - 5<em>V</em>)

<em>X</em> d<em>V</em>/d<em>X</em> = (2 - <em>V</em>) / (6 - 5<em>V</em>) - <em>V</em>

<em>X</em> d<em>V</em>/d<em>X</em> = (2 - <em>V</em> - (6 - 5<em>V</em>)) / (6 - 5<em>V</em>)

<em>X</em> d<em>V</em>/d<em>X</em> = (4<em>V</em> - 4) / (6 - 5<em>V</em>)

- (5<em>V</em> - 6) / (4<em>V</em> - 4) d<em>V</em> = 1/<em>X</em> d<em>X</em>

Integrate both sides:

-5/4 <em>V</em> + 1/4 ln|4<em>V</em> - 4| = ln|<em>X</em>| + <em>C</em>

Extract a constant from the logarithm on the left:

-5/4 <em>V</em> + 1/4 (ln(4) + ln|<em>V</em> - 1|) = ln|<em>X</em>| + <em>C</em>

-5/4 <em>V</em> + 1/4 ln|<em>V</em> - 1| = ln|<em>X</em>| + <em>C</em>

-5<em>V</em> + ln|<em>V</em> - 1| = 4 ln|<em>X</em>| + <em>C</em>

Get this back in terms of <em>Y</em> :

-5<em>Y/X</em> + ln|<em>Y/X</em> - 1| = 4 ln|<em>X</em>| + <em>C</em>

Now get the solution in terms of <em>y</em> and <em>x</em> :

-5 (<em>y</em> - 1/2)/(<em>x</em> + 1/4) + ln|(<em>y</em> - 1/2)/(<em>x</em> + 1/4) - 1| = 4 ln|<em>x</em> + 1/4| + <em>C</em>

<em />

With some manipulation of constants and logarithms, and a bit of algebra, we can rewrite this solution as

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|(4<em>y</em> - 4<em>x</em> - 3)/(4<em>x</em> + 1)| = 4 ln|<em>x</em> + 1/4| + 4 ln(4) + <em>C</em>

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|(4<em>y</em> - 4<em>x</em> - 3)/(4<em>x</em> + 1)| = 4 ln|4<em>x</em> + 1| + <em>C</em>

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|4<em>y</em> - 4<em>x</em> - 3| - ln|4<em>x</em> + 1| = 4 ln|4<em>x</em> + 1| + <em>C</em>

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|4<em>y</em> - 4<em>x</em> - 3| = 5 ln|4<em>x</em> + 1| + <em>C</em>

8 0
3 years ago
Calculate each mountain path grade to the nearest .
nordsb [41]
I’m not exactly sure how to calculate the grade, but this is what I’ve done below. Hope it helps!
5 0
3 years ago
ANSWER ASAP !!!!!!!!!!
tekilochka [14]
Option C is correct or y=3/4x-5. Use the given functions to set up and simplify y=mx+b
to find the equation.
6 0
3 years ago
An HMO pamphlet contains the following recommended weight for women: "Give yourself 100 pounds for the first 5 feet plus 5 pound
fenix001 [56]

Answer: 5 feet and 7 inches

Step-by-step explanation:

"Give yourself 100 pounds for the first 5 feet plus 5 pounds for every inch over 5 feet tall"

100 pounds for 5 feet + 5 pounds/inch [over 5 feet]

We can separate 135 pounds into two parts: the first 100 pounds and the other 35 pounds: 135 = 100 + 35

100 = 5 feet

35 pounds/5 pounds/inch = 7 inches

So, the height is 5 feet and 7 inches

7 0
3 years ago
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