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Thepotemich [5.8K]
2 years ago
10

The sum of two number is 1000 and the difference between their square is 256000 find the numbers.​

Mathematics
1 answer:
Leto [7]2 years ago
8 0

Answer:answer it yourself

Step-by-step explanation:

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The sum of two numbers is 39 and the difference is 3. What are the numbers?
frosja888 [35]

Answer: 21 & 18

Step-by-step explanation:

Sum of two numbers is 39

Difference is 3

Let the numbers be x & y

X+y=39........equation 1

X-y=3...........equation 2

X=3+y............equation 3

Substitute equation 3 into equation 1

(3+y)+y=39

3+y+y=39

3+2y=39

2y=39-3

2y=36

Y=36/2

Y=18

Substitute for y in equation 2

X-y=3

X-18=3

X=3+18

X=21

The two numbers are 21 & 18

8 0
3 years ago
Suppose that we are testing a coin to see if it is fair, so our hypotheses are: H0: p = 0.5 vs Ha: p ≠ 0.5. In each of (a) and (
aleksley [76]

Answer:

H_0: p = 0.5\\H_a: p \neq 0.5

a. We get 56 heads out of 100 tosses.

We will use one sample proportion test  

x = 56

n = 100

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{56}{100}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}

                                       =1.2

refer the z table for p value

p value = 0.8849

a.  We get 560 heads out of 1000 tosses.

We will use one sample proportion test  

x = 560

n = 1000

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{560}{1000}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}

                                       =3.794

refer the z table for p value

p value = .000148

p value of part B is less than Part A because part B have 10 times the number the tosses.

6 0
2 years ago
What (3×5^2)/(5)^2 equal? Plz answer fast and with work and I will give brainliest
balu736 [363]

Answer:

The answer is 3.

Step-by-step explanation:

Given that the Indices Law is,

{a}^{m}  \div  {a}^{n}  =  {a}^{m - n}

{a}^{0}  = 1

So the expression is :

3 \times  {5}^{2}  \div  {5}^{2}

= 3 \times  {5}^{2 - 2}

= 3 \times  {5}^{0}

= 3 \times 1

= 3

4 0
3 years ago
Vertex: <br> (<br> 2<br> ,<br> 0<br> )<br> , Passes through: <br> (<br> 5<br> ,<br> −<br> 18<br> )
NemiM [27]

Answer:

2>0                5>-18

Step-by-step explanation:

8 0
2 years ago
-4 &gt; x - 3 find x in the equation
dimulka [17.4K]

Answer:

X= -1

Step-by-step explanation:

8 0
2 years ago
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