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3 years ago

Middle school math.

Mathematics

2 answers:

Nonamiya [84]3 years ago

7 0

The last one the reason is 2 is how much weeks so it’d be 2x - 126 cause that’s how much she wants to lose

Nady [450]3 years ago

4 0

Answer: d or the last one

Step-by-step explanation:

The last one because she wants to lose 2 pounds per week and of x is the amount of weeks she does it for and 126 is the amount she already weighs, then the equation would be y=2x - 126

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If you start with a number, add 5 , then multiply by 7, the result is133. what was the original number?

Natalija [7]

(x+5)*7=133
7x+35=133
7x=98
x=98/7
x=14

5 0

3 years ago

Expand and simplify 2(5x - 1) – (2x - 5)

horrorfan [7]

Answer:

2(5x - 1) – (2x - 5)

=2(5x−1)−2x+5

=10x−2−2x+5

=(10x−2x)+(−2+5)

=8x+3

Step-by-step explanation:

3 0

3 years ago

How do I do this? Can somebody answer and explain?

yan [13]

A) multiple the 3 x 4 and add 1.
3 x 4 = 12 + 1 = 13
13/3

B) (7 x 3) + 2 = 23/3

C) (4 x 2) + 1 = 9/2

D) (2 x 8) + 7 = 23/8

5 0

2 years ago

Read 2 more answers

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

5 0

3 years ago

800,00 rounded to the nearest hundred thousand

lisov135 [29]

It is 80,000 im not sure what you meant by "800,00"

8 0

3 years ago

Middle school math.​

Middle school math.