Since you're looking for the chance that the defective player occurs twice, you need to find the chance your friend receives a defective player given that you also receive one. The chance you receive a defective player is 4%, or 0.04. If you friend also receives a defective player, then the chance of both occurring is 4% of 4%, or 0.04 * 0.04, which equals 0.0016. So the probability that you can a friend both receive a defective player is 0.16%.
Answer:
1/7
Step-by-step explanation:
It's the only option that doesn't give a whole number
Answer:
Step-by-step explanation:
To solve, you start with distributive property and multiply 7 by n and 3 for
7n-21<-63 the you get the 7n alone by adding 21 to -63 and the 21 for 7n<-42. now you divide 7 by itself and 42 for n<-6
Answer:
30
Step-by-step explanation:
60(highest) - 30(lowest) = 30(range)
